The West Virginia Radio Stations 92.9 FM desires to estimate the proportion of the market they hold with a maximum error of 0.1 and confidence interval of 0.95.
How large sample would be required to estimate the fraction of listeners to within the desired level of accuracy? Since we don't know the true population portion, we assume the previous point estimate of 0.117 is the true proportion.
Hint: p = 0.117; z_(a/2) = 1.96 for 95% confidence and error = 0.01
a. 3969 |
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b. 9604 |
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c. 4000 |
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d. 3499 |
The West Virginia Radio Stations 92.9 FM desires to estimate the proportion of the market they...