Men’s heights are normally distributed with a mean of 69.0 inches and a standard deviation of...
Men’s heights are normally distributed with a mean of 69.0 inches and a standard deviation of 2.8 inches.
a) What is the probability that a man selected at random is at least 72 inches tall? Round the answer to 4 decimal places.
b) The Mark VI monorail used at Disney World has doors with a height of 72 inches. What doorway height would allow 98% of adult men to fit without bending?
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Men’s heights are normally distributed with a mean of 69.0
inches and a standard deviation of...
(30 points) The MARK VI monorail at Disney World has doors with a height of 72...
(30 points) The MARK VI monorail at Disney World has doors with a height of 72 inches. Heights of men are normally distributed with a mean of 68.6 in. and a standard deviation of 2.8 in. 4. a. What percentage of adult men can fit through the door without bending? Explain. b. If a car is loaded with 60 randomly selected men, what is the probability that their mean height is less than 72 in.? Explain.
The Mark VI monorail used at Disney World has doors with a height of 72in. Heights...
The Mark VI monorail used at Disney World has doors with a height of 72in. Heights of men are normally distributed with a mean of 69.5in and a standard deviation of 2.4 in. What percentage of adult men can fit through the doors without bending?
2) Women's heights are normally distributed with a mean of 64.1 in, and a standard deviation...
2) Women's heights are normally distributed with a mean of 64.1 in, and a standard deviation of 2.5in. a) What percentage of adult women can fit through the doors on the Mark VI monorail (find the height of the doors on the Monorail in the chapter 5 notes)? b) Does the answer to part a mean that all women are under 6 ft tall? If not, explain the probability in a complete sentence by converting it to a fraction. c)...
12A survey found that women's heights are normally distributed with mean 63.3 in. and standard deviation...
12A survey found that women's heights are normally distributed with mean 63.3 in. and standard deviation 2.3 in. The survey also found that men's heights are normally distributed with a mean 67.3 in. and standard deviation 92.9. Complete parts a through c below. The percentage of women who meet the height requirement is ____ Find the percentage of men meeting the height requirement. _____ If the height requirements are changed to exclude only the tallest 5% of men and the...
A survey found that women's heights are normally distributed with mean 63.6 in and standard deviation...
A survey found that women's heights are normally distributed with mean 63.6 in and standard deviation 3.7 in. The survey also found that men's heights are normally distributed with mean of 69.9 in and standard deviation 3.7 in. Consider an executive jet that seats six with a doorway height of 56.3 in. Complete parts a through c below: a-What percentage of adult men can fit through the door without bending? - What doorway height would allow 40% of men to...
Heights of men are normally distributed with a mean of 69.0 inches and a standard deviation...
Heights of men are normally distributed with a mean of 69.0 inches and a standard deviation of 2.8 inches. What is the probability that a randomly selected group of 16 men have a mean height greater than 71 inches.
Adult men have heights with a mean of 69.0 inches and a standarddeviation of 2.8...
Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Find the z-score of a man 59.9 inches tall. (to 2 decimal places)Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Find the height of a man with a z-score of 1.8929
A survey found that women's heights are normally distributed with mean 62.4 in and standard deviation...
A survey found that women's heights are normally distributed with mean 62.4 in and standard deviation 2.1 in. The survey also found that men's heights are normally distributed with mean 68.5 in and standard deviation 3.1 in. Consider an executive jet that seats six with a doorway height of 55.6 in.a. What percentage of adult men can fit through the door without bending? The percentage of men who can fit without bending is
Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8...
Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Find the z-score of a man 73.8 inches tall. (to 2 decimal places)
A survey found that women's heights are normally distributed with mean 63.7 in. and standard deviation 2.1 in.
A survey found that women's heights are normally distributed with mean 63.7 in. and standard deviation 2.1 in. The survey also found that men's heights are normally distributed with mean 69.2 in. and standard deviation 3.4 in. Consider an executive jet that seats six with a doorway height of 55.8 in. Complete parts (a) through (c) below. a. What percentage of adult men can fit through the door without bending? The peroentage of men who can fit without bending is _______ %. (Round...
(30 points) The MARK VI monorail at Disney World has doors with a height of 72 inches. Heights of men are normally distributed with a mean of 68.6 in. and a standard deviation of 2.8 in. 4. a. What percentage of adult men can fit through the door without bending? Explain. b. If a car is loaded with 60 randomly selected men, what is the probability that their mean height is less than 72 in.? Explain.
2) Women's heights are normally distributed with a mean of 64.1 in, and a standard deviation of 2.5in. a) What percentage of adult women can fit through the doors on the Mark VI monorail (find the height of the doors on the Monorail in the chapter 5 notes)? b) Does the answer to part a mean that all women are under 6 ft tall? If not, explain the probability in a complete sentence by converting it to a fraction. c)...
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