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A person is taking a 12​-question ​multiple-choice test for which each question has three answer​ choices,...

A person is taking a 12​-question ​multiple-choice test for which each question has three answer​ choices, only one of which is correct. The person decides on answers by rolling a fair die and marking the first answer choice if the die shows 1 or​ 2, the second if it shows 3 or​ 4, and the third if it shows 5 or 6. Find the probability that the person gets fewer than 3 correct answers.

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Answer #1

This will be a binomial distribution with parameters:

n = 12, p = 1/3

Hence,

P(Fewer than 3 correct)

= P(0) + P(1) + P(2)

= 0.1811

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