Question

A lead object and a quartz object each have the same initial volume. The volume of each increases by the same amount, because the temperature increases. If the temperature of the lead object increases by 3.5 °C, by how much does the temperature of the quartz object increase? (The coefficient of volume expansion for lead is 8.70 × 10 − 5 o C − 1 and that one for quartz is 1.50 × 10 − 6 o C − 1 )

Answer 1

dV = beta*Vo*dT

beta = coefficient of volume expansion

both lead and quartz objects experience the same change in volume

dVlead = dVqurtz

beta_lead * Vo*dTlead = beta_quartz*Vo*dTquartz

dTquartz = beta_lead*dTlead/beta_quartz

dTquartz = (8.7 x 10^-5 * 3.5) / 1.5 x 10^-6

dTquartz = 203 oC