Question

If necessary, create a new project named Intermediate24 Project and save it in the
Cpp8\Chap14 folder. Also create a new source file named Intermediate24.cpp. If you
are using Microsoft Visual C++, copy the Intermediate24.txt file from the Cpp8\Chap14
folder to the Cpp8\Chap14\Intermediate24 Project folder. Use a text editor to open
the Intermediate24.txt file, which contains payroll codes and salaries. Close the
Intermediate24.txt file. Create a program that allows the user to enter a payroll
code. The program should search for the payroll code in the file and then display the
appropriate salary. If the payroll code is not in the file, the program should display an
appropriate message. The program should allow the user to display as many salaries as
needed without having to run the program again. Save and then run the program.
Test the program by entering the following payroll codes: 10, 24, 55, 32, and 6. Stop
the program.

Please use intermediate24.txt file =

1#23400
4#17000
5#21000
6#12600
9#26700
10#18900
11#18500
13#12000
15#49000
16#56500
20#65000
21#65500
22#78200
23#71000
24#71100
25#72000
30#83000
31#84000
32#90000

and finish using this code

#include <iostream>
#include <fstream>
using namespace std;

int main()
{
   int searchFor = 0;
   int code = 0;
   int salary = 0;
   char found = 'N';
   char another = 'Y';

   ifstream inFile;

   while (another == 'Y')
   {
       inFile.open("Intermediate24.txt", ios::in);
       if (inFile.is_open())
       {
           // enter the needed logic here
           // for entering the payroll code

           while (!inFile.eof() && found == 'N')
           {
               // keep searching for the payroll code
               // until EOF

           }   //end while
           inFile.close();

           if (found == 'Y')
               // if the code is found, do something...
           else
               cout << "Invalid payroll code"
                   << endl << endl;
           //end if

           found = 'N';
           cout << "Search for another code (Y or N)? ";
           cin >> another;
           another = toupper(another);
       }
       else
       {
           cout << "The Intermediate24.txt file could not be opened." << endl;
           another = 'N';
       }   //end if
   }   //end while
   return 0;
}   //end of main function

Answer 1

The code is self explanatory and variables have been named appropriately.

Please refer to the screenshots for the indentation:

please comment before downvoting if any doubt, will resolve asap.

Code:

#include <iostream>

#include <fstream>

using namespace std;

int main()

{

int searchFor = 0;

int code = 0;

int salary = 0;

char found = 'N';

char another = 'Y';

string payroll_code;

ifstream inFile;

while (another == 'Y')

{

inFile.open("Intermediate24.txt", ios::in);

if (inFile.is_open())

{

cout << "Enter the Payroll Code : "; // logic for getting the payroll code

cin >> payroll_code ;

cout << endl;

string line;

while (!inFile.eof() && found == 'N')

{

getline(inFile,line);

for(int i = 0; i < line.length(); i++)

{

if(line[i] == '#')

{

string cur_payroll = line.substr(0,i);

if(cur_payroll == payroll_code)

{

salary = stoi(line.substr(i+1));

found = 'Y';

break;

}

}

}

}

inFile.close();

if (found == 'Y') // if the code is found, print the salary

{

cout << "The salary for the given payroll is : " << salary << endl;

}

else

cout << "Invalid payroll code"

<< endl << endl;

//end if

found = 'N';

cout << "Search for another code (Y or N)? ";

cin >> another;

another = toupper(another);

}

else

{

cout << "The Intermediate24.txt file could not be opened." << endl;

another = 'N';

} //end if

} //end while

return 0;

} //end of main function

Screenshots:

Code:

Sample run: