Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 57.4 degrees. Low Temperature (°F) Frequency 40-44 1 45-49 5 50-54 9 55-59 5 60-64 1
Class interval | Mid-point: Xi | Frequency: fi | Xifi |
40-44 | 42 | 1 | 42 |
45-49 | 47 | 5 | 235 |
50-54 | 52 | 9 | 468 |
55-59 | 57 | 5 | 285 |
60-64 | 62 | 1 | 62 |
=21 | =1,092 |
Mean, = =1092/21 =52
So, the computed mean of 52 degrees < actual mean of 57.4 degrees.
(It's because each mid-point is not the actual center (average) of values in that class interval and so is the difference between computed and actual mean values).
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