If the following equation, Cr+3 + HClO4 ----------- Cr2O7-2 + Cl-, is balanced by the ion-electron method in acid solution, a correct term in the balanced equation is
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If the following equation, Cr+3 + HClO4 ----------- Cr2O7-2 + Cl-, is balanced by the ion-electron...
write the balanced equation for the following reaction in acidic solution: Cr2O7 ^2- + C2H6O---> Cr^3+ + C2H4O
Balance the equation in aqueous acidic solution: Cr2O7^2-(aq) + SO3^2-(aq) → SO4^2-(aq) + Cr^3+(aq)
Balance the following redox equations by the ion-electron half-reaction method: (a) (acid solution): MnO2 (s) + Cl → Mn2+ + Cl2 (g) (b) (acid solution): NaBiO; (s) + Ce3+ BiO+ + Ce4+ + Na+ (c) (basic solution): Fe(OH)2 (s) + CrO42- → Fe,0, (s) + Cr(OH)4
3. Balance the following redox equations by the ion-electron half-reaction method: (a) (acid solution): Cr0(aq) + U" (aq) → Cr" (aq) +UO; (aq) (b) (acid solution): Cr(s) + O2(g) → Cr* (aq) (C) (basic solution): P. (s) + OH' (aq) → PH; (g) + H2PO2 (aq)
Write a balanced half-reaction for the oxidation of chromium ion Cr+3 to dichromate ion Cr2O−27 in basic aqueous solution.
Question 1 (4 points) Given the following balanced equation Cr, 0,2- + 3 H2O +8 H+ + 2 Cr3+ + 3 0, +7H,O What is the total number of electrons transferred in the balanced reaction? Please enter a number. What is the oxidation number of Cr in the dichromate ion? Please enter a number such as +2 or -2.
(a) Balance the following half-reactions by the ion-electron half-reaction method: (i) (acid solution) Cl– (aq) → ClO3– (aq) (ii) (acid solution) MoO3 (s) → Mo (s) (iii) (base solution) P4 (s) → H2PO2– (aq) (iv) (base solution) Se (s) → SeO32– (aq) (b) Which of the above equations are oxidation half-reactions? (c) Give the formulas of the reactants that become oxidized in the course of the reaction.
Select the chemical equation that is balanced: 2 Cr + 3 HCl → 2 CrCl3 + 3 H2 2 Cr + 6 HCl → 2 CrCl3 + 3 H2 Cr + 3 HCl → CrCl3 + 3 H2
balance the following equation by the ion electron method: Balance the following equation by the ion-electron method: Cr2O3 + H2S --> Crd+ + S O A 14H+ + Cr203- + H2S --> 2Cr3+ + S + 7H20 o B 8H+ + Cr202 + H2S - - > 2Cr3+ + S + 7H20 O C 8H+ + Cr203- + 3H2S - - > 2Cr3+ + 35 + 7H20 O D 14H+ + Cr2O3 + H2S - - > Cr3+ + S...
Balance the following redox equations by the ion-electron half-reaction method: (a) (acid solution): VŽ+ + V(OH). - VO2 (b) (acid solution): C 02 + MnO - CO2(g) + Mn (c) (basic solution): Cr(OH), (s) + H2O2 → CrO