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There are 5 different French books and 5 different Spanish books. What is the probability that...

There are 5 different French books and 5 different Spanish books. What is the probability that the books of the same language are grouped together?

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Answer #1

Number of ways to arrange n items = n!

Number of ways to arrange 5 French books = 5! = 120

Number of ways to arrange 5 Spanish books = 5! = 120

Number of ways to arrange 10 books such that 5 French books and 5 Spanish books are toether (5 Spanish first and then 5 French + 5 Vrench and then 5 Spanish) = 2 x 120 x 120

= 28,800

Number of ways to arrange 10 books = 10!

= 3,628,800

P(the books of the same language are grouped together) = 28,800/3,628,800

= 1/126

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