There are 5 different French books and 5 different Spanish books. What is the probability that the books of the same language are grouped together?
Number of ways to arrange n items = n!
Number of ways to arrange 5 French books = 5! = 120
Number of ways to arrange 5 Spanish books = 5! = 120
Number of ways to arrange 10 books such that 5 French books and 5 Spanish books are toether (5 Spanish first and then 5 French + 5 Vrench and then 5 Spanish) = 2 x 120 x 120
= 28,800
Number of ways to arrange 10 books = 10!
= 3,628,800
P(the books of the same language are grouped together) = 28,800/3,628,800
= 1/126
There are 5 different French books and 5 different Spanish books. What is the probability that...
There are 5 different French books and 5 different Spanish books. How many ways are there to arrange them on a shelf if: (a) Books of the same language are grouped together, French on the left, Spanish on right? (b) French & Spanish books must alternate in the grouping, beginning with a French book?
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