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a. No, the relationship is not significant. We have conducted an ANOVA test here to determine if the relationship is significant with H0: the relationship is not significant and H1:the relationship is significant.
The p-value of the test here is greater than the standard value of 0.05 which is considered as the alpha level to determine if a test is significant or not. So we fail to Reject the null hypothesis here.
b. From the ANOVA test we find that the relationship between IV and DV is not significant at the 5% significance level.
Sum of Squares df Mean Square F Sig. Between Groups 13.114 4 3.279 2.230 .072...
ANOVA Score Sum of Squares df Mean Square F Sig. Between Groups 652.875 3 217.625 14.404 .000 Within Groups 543.900 36 15.108 Total 1196.775 39
Question 8 ANOVA Score Sum of Squares df Mean Square F Sig. Between Groups 1746.100 3 582.033 47.686 .000 Within Groups 439.400 36 12.206 Total 2185.500 39 Which value below represents the effect size (eta squared) for this analysis? η2 =.83 η2 =.79 η2 =.59 η2 =.69
Question 24 (4 points) DepScore1 Sum of Squares df F 1.313 Mean Square 23.846 18.158 Sig. 2 74 Between Groups Within Groups Total 47.693 1761.307 1809.000 97 99 Using the output above, report the results of this test using APA format. Question 25 (3 points) Given the above findings, report what you found in terms the null hypothesis using an Alpha level of .05.
Mean Square (Variance) Degrees of Sum of Source Freedom Squares Consider an experiment with nine groups, with eight values in each. For the ANOVA summary table shown to the right, fill in all the missing results. Among FSTAT ? MSA 22 SSA ? c-1 ? groups Within MSW ? SSW 693 n c groups Total SST ? n-1 2 Complete the ANOVA summary table below. Degrees of Freedom Sum of Mean Square (Variance) MSA 22 Source Squares FSTAT Among groups...
Complete the following ANOVA summary table using the appropriate formulas. Source Sum of Square df Mean Square Fobt Between groups 1,059 18 Within groups 3,702 167 N/A Total 4,761 185 N/A N/A Calculate the Mean Squared Between (bn)? Calculate the Mean Squared Within (wn)? Finally, calculate the F-Statistic or F-obtained?
Source Between treatments Within treatments Sum of Squares (Ss) df Mean Square (MS) 2 310,050.00 2,650.00 In some ANOVA summary tables you will see, the labels in the first (source) column are Treatment, Error, and Total Which of the following reasons best explains why the within-treatments sum of squares is sometimes referred to as the "error sum of squares"? O Differences among members of the sample who received the same treatment occur when the researcher O Differences among members of...
Source of Variation Sum of Squares Degrees of Freedom Mean Square F Between Treatments 180 3 Within Treatments (Error) TOTAL 480 18 If at 95% confidence, we want to determine whether or not the means of the populations are equal, the p-value is between 0.01 to 0.025 between 0.025 to 0.05 between 0.05 to 0.1 greater than 0.1
Source of Variation Sum of Squares Degrees of Freedom Mean Square F Between Treatments 64 8 Within Treatments 2 Error Total 100 If at 95% confidence we want to determine whether or not the means of the populations are equal, the p-value is greater than 0.1 between 0.05 to 0.1 between 0.025 to 0.05 less than 0.01
5. Identify the following: k (number of groups or samples) N, (number of cases within each group or sample) N (total number of cases) df (between-groups degrees of freedom)= How is it calculated? df (within-groups degrees of freedom) How is it calculated? critical value for F (using the F table) SSB (Sum of Squares Between groups) = ssw (Sum of Squares Within groups) Mean square between= How is it calculated? Mean square within= How is it calculated? F ratio (test...
Case Study # 1. A sample of 10 fish is randomly selected from a normally distributed population of Indian River Lagoon fishes. Each fish is weighed and measured and then dissected to remove the otoliths (or ear stones), which are also measured. The distribution of otolith length and fish mass is approximately normal. A statistical analysis of this case study shows the following results: T= 0.8386 (P <0.05) Otolith Length (mm) 150 300 Fish Mass (9) Figure Z. A scatter...