One student conducts an acid-base reaction where she finds the following results. What is the enthalpy...
One student conducts an acid-base reaction where she finds the following results. What is the enthalpy of the reaction (in KJ/mol)?
Heat gained by solution 2856 J
Heat gained by calorimeter 156 J
Moles of product formed 0.113 mol
Homework Answers
Heat gained by solution = 2856 J
Heat gained by calorimeter = 156 J
Heat change for solution = (Heat gained by solution) + (Heat gained by calorimeter)
Heat change for solution = (2856 J) + (156 J)
Heat change for solution = 3012 J
Heat change for reaction = -(Heat change for solution)
Heat change for reaction = -(3012 J)
Heat change for reaction = -3012 J
enthalpy of reaction = (Heat change for reaction) / (moles of product formed)
enthalpy of reaction = (-3012 J) / (0.113 mol)
enthalpy of reaction = -26654.87 J/mol
enthalpy of reaction = -26.65 kJ/mol
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