If work done by the system on the surroundings. Then system lost some energy, so internal energy of the gas inside the piston decreases. So change in internal energy delta E = negative value.
Change in enthalpy of the coffee = -(amount of energy lost by coffee)
= - 50 kJ
If there is no work in the process then delta H = delta E
That means in isochoric process (at constant volume)
- If a gas-filled piston in a car engine does work on the surrounding engine parts,...
Enthalpy, Internal Energy and PV Work -Muvable piston Heating Coil Gas An electrical heater delivers 8.600 k) of energy (as heat) to a system consisting of the gas inside a cylinder having a movable piston. As a result, the piston moves against a constant external pressure such that P AV = 2.580 k). What is the change in internal energy for the system? Answer to the nearest 0.001 k). Submit Answer Tries 0/5 a Post Discussion Send Feedback
1. In the compression stroke of a gas engine, the work done on the gas by the piston is 70 kJ/kg, and the heat rejected to the cooling water is 42 kJ/kg. Calculate lthe change of specific internal energy, stating whether it is a gain or a loss. 2. A closed system undergoes 5 separate processes. These processes are summarised in the following table Q (kJ) E, (kJ) 20 50 Process E, (kJ) AE (k 50 20 -20 80 90...
Please solve all parts, showing work. Included is an equation sheet for reference. Some numbers you should get (please still solve all parts) are b) 81.2 mol c) 1.013 Mpa d) 1554 K e) Wcyc= 1595 J f) deltaEint12= 4559 J g) Q31= -2964 J i) deltaS13= 3.888 J/K Thank you in advance! 1) (60 points) A heat engine uses air (diatomic as the working muid in a three-step cycle. First, a volume of 2 L (2 x 10-3 m3)...
answer all please Walan 6 Iron metal reacts with chlorine gas according to the equation: 2Fe(s) + 3Cl2(g) 2FeCl(s) T135.0 g each of iron and chlorine react, how much FeCl, will be formed? A 102 g B 155 g 53.48 D. 80.08 E 68.0 8 7. In the process of obtaining lead from Pbs, or galena the galena is "roasted" (heated in the presence of oxygen), so that the following reaction occurs: 2PbS(s) + 30,(g) 2PO(S) + 2SOxg) IF 50.0...
Can you please show how to do the calculations I sent for run 2. al values ofc where the o the maximum ot minim changes? lluirate by ggh ily gven by the oquatice lcrmining the transinoal f inflection poses change abe famly to see whas shand oonal value of c at whi unges. Try to discover i a have discoveed anomials given by the oqu Er what values of c does Exp Background Information We A chemical reaction involves breaking,...
summatize the following info and break them into differeng key points. write them in yojr own words apartus 6.1 Introduction—The design of a successful hot box appa- ratus is influenced by many factors. Before beginning the design of an apparatus meeting this standard, the designer shall review the discussion on the limitations and accuracy, Section 13, discussions of the energy flows in a hot box, Annex A2, the metering box wall loss flow, Annex A3, and flanking loss, Annex...
summarizr the followung info and write them in your own words and break them into different key points. 6.5 Metering Chamber: 6.5.1 The minimum size of the metering box is governed by the metering area required to obtain a representative test area for the specimen (see 7.2) and for maintenance of reasonable test accuracy. For example, for specimens incorporating air spaces or stud spaces, the metering area shall span an integral number of spaces (see 5.5). The depth of...
just one example/demonstration! Data needed to be calculated is in highlighted in green boxes. And I highlighted in red an equation (not sure if thats what you use to calculate it) And ignore the lab instructions on completeing a graph!! I already know how to do that in excel, just curious how Ln (relative rate) and 1/T in K^-1 is calculated by hand* here is the rest of that lab leading up to the question as I know its typically...
For the preparation and standardization of NaOH with KHP im supposed to boil water for 1hr and 30 min to remove CO2....the problem is that if I don't boil it for that long and (30 min) b/c of not enough time but I put the water I boiled for 1/2 hr aproximately into a NaOH bottle with a CO2 absorber and stored it there for a few days. I would assume that I would have to boil the water again...but...