In a survey of 639 males ages 18-64, 398 say they have gone to the dentist in the past year. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. The 90% confidence interval for the population proportion p is ( nothing, nothing). (Round to three decimal places as needed.) The 95% confidence interval for the population proportion p is ( nothing, nothing). (Round to three decimal places as needed.) Interpret your results of both confidence intervals. A. With the given confidence, it can be said that the population proportion of males ages 18-64 who say they have gone to the dentist in the past year is between the endpoints of the given confidence interval. B. With the given confidence, it can be said that the sample proportion of males ages 18-64 who say they have gone to the dentist in the past year is between the endpoints of the given confidence interval. C. With the given confidence, it can be said that the population proportion of males ages 18-64 who say they have gone to the dentist in the past year is not between the endpoints of the given confidence interval. Which interval is wider? The 90% confidence interval The 95% confidence interval
The 90% confidence interval for the population proportion p is ( 0.591 , 0.654 ) .
The 95% confidence interval for the population proportion p is ( 0.585 , 0.660 )
With the given confidence, it can be said that the population proportion of males ages 18-64 who say they have gone to the dentist in the past year is between the endpoints of the given confidence interval.
The 95% confidence interval is wider.
In a survey of 639 males ages 18-64, 398 say they have gone to the dentist...
In a survey of 628 males ages 18-64, 394 say they have gone to the dentist in the past year. oportion n er re the results and compare he wa ns onstruct 90% and 95% confidence intervals or the population The 90% confidence interval for the population proportion p is ( Round to three decimal places as needed.) The 95% confidence interval for the population proportion p is (Round to three decimal places as needed.) Interpret your results of both...
In a survey of 662 males ages 18-64, 397 say they have gone to the dentist in the past year. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. The 90% confidence interval for the population proportion p is ( nothing, nothing). (Round to three decimal places as needed.) The 95% confidence interval for the population proportion p is...
In a survey of 609 males ages 18-64, 395 say they have gone to the dentist in the past year. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. The 90% confidence interval for the population proportion p is ( , ). (Round to three decimal places as needed.)
In a survey of 2673 adults, 1400 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results. A 99% confidence interval for the population proportion is left parenthesis nothing comma nothing right parenthesis . (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. A. With 99% confidence, it can be said that the sample proportion of adults who say they have...
In a survey of 2330 adults, 700 say they believe in UFOs. Construct a 95 % confidence interval for the population proportion of adults who believe in UFOs. A 95% confidence interval for the population proportion is ( nothing, nothing). (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. A. With 95% probability, the population proportion of adults who do not believe in UFOs is between the endpoints of the given confidence interval. B....
In a survey of 2283 adults in a recent year, 1366 say they have made a New Year's resolution. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. The 90% confidence interval for the population proportion pis (D. (Round to three decimal places as needed.) The 95% confidence interval for the population proportion pis ( I. (Round to three decimal places as needed.) With the given confidence, it...
In a survey of 2834 adults, 1448 say they have started paying bills online in the last year Construct a 99% confidence interval for the population proportion. Interpret the results. A 99% confidence interval for the population proportion is (0) (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. O A. With 99% confidence, can be said that the population proportion of adults who say they have started paying bills online the last year...
In a survey of 2850 adults, 1443 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results. A 99% confidence interval for the population proportion is (0. (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. O A. With 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the...
tion In a survey of 2973 adults, 1424 say they have started paying bills online in the last year Construct a 99% confidence interval for the population proportion Interpret the results A 99% confidence interval for the population proportion is (Round to three decimal places as needed) Interpret your results. Choose the correct answer below. OA. The endpoints of the given confidence interval show that adults pay bills online 99% of the time. OB. With 99% confidence, it can be...
In a survey of 3384 adults, 1437 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results. L .D. A 99% confidence interval for the population proportion is (L (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. O O O A. With 99% confidence, it can be said that the sample proportion of adults who say they have started paying...