If the heat necessary to warm 530.0 g of water from a
temperature of T1 = 20.0 °C to T2 = 87.0 °C
were somehow converted to translational kinetic energy of this
amount of water, what would be the speed of this water?
Heat, Q = m C dT
Q = 0.53 x 4186 x (87 - 20) = 1.48 x 10^5 J
Kinetic energy, E = 0.5 mv^2
1.48 x 10^5 = 0.5 x 0.53 v^2
Velocity, v = 748.95 m/s
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