Given an int variable k that has already been declared, use a while loop to print a single line consisting of 97 asterisks. Use no variables other than k.
PLEASE ANSWER IN C
Given an int variable k that has already been declared while loop to print a single line consisting of 97 asterisks is
k = 97; while(k>0){ printf("*"); k--; }
Given an int variable k that has already been declared, use a while loop to print...
Convert the following while loop into a for loop. int 1 - 50: int sum-07 while (sum < 1000) sum - sum + 1; Question 35 (2 points) Saved Given an int variable k that has already been declared, use a while loop to print a single line consisting of 80 dollar signs. Use no variables other than k. int sum = 0; for(int i = 100;sum < 10000;1-- sum = sum + i;
java : Given an int variable n that has been initialized to a positive value and, in addition, int variables k and total that have already been declared, use a do...while loop to compute the sum of the cubes of the first n whole numbers, and store this value in total. Use no variables other than n, k, and total.
Write in C: Assume that an int variable age has been declared and already given a value and assume that a char variable choice has been declared as well. Assume further that the user has just been presented with the following menu: S: hangar steak, red potatoes, asparagus T: whole trout, long rice, brussel sprouts B: cheddar cheeseburger, steak fries, cole slaw (Yes, this menu really IS a menu!) Write some code that reads a single character (S or T...
Assuming that the array upc declared below has already been filled with MAX_LENGTH values, write a function that will ask to input an integer from the keyboard and perform a sequential search of the array for the input integer. If the input integer is found, print the index of the matching value in the array. Otherwise, print "Not found". Include declarations for all variables that you use. const int MAX_LENGTH = 25; int upc[MAX_LENGTH]; Please write in C++
Given an int variable n that has already been declared, write some code in C that repeatedly reads a value into n until at last a number between 1 and 10 (inclusive) has been entered.
Given that two int variables, total and amount, have been declared write a loop that reads non-negative values into amount and adds them into total. The loop terminates when a value less than 0 is read into amount. Don't forget to initialize total to 0. To read a value into amount use a method, getNum() that we provide for you a class named TC: amount = TC.getNum(); Instructor Notes: amount = TC.getNum(); TC is the name of a class program....
Please solve this in Java. Assume we have already defined a variable of type int called num with the following line of code: int num = ???; // 'num' can have any int value TASK: Print a Triforce composed of 3 centered triangles created with num asterisks (*) on the bottom row, num - 2 asterisks on the next bottom row, ..., and 1 asterisk on the top row, and such that the triangles are surrounded by hyphens (-). You...
Given a double variable named x that has been declared and given a value, let's use a binary search technique to assign an estimate of its square root to another double variable, root that has also been declared. Let's assume that x's value is greater than 1.0 -- that will simplify things a bit. Here's the general idea: Since x>1, we know its square root must be between 1 and x itself. So declare two other variables of type double...
In C An array ints of integers has already been declared and initialized. A function printint has been defined with the following prototype: void printint(int *); Write code that will call printint with a pointer to the second value in the array ints. Note: you will not need to declare an int variable.
For the C code 1 int loop while(int a, int b) int result 1; while (a < b) t result (atb); return result; Gcc generates the following assembly code: %ebp+8, mov1 movl movl %ebp+12 at 8(%ebp) ,%ecx 12(%ebp) ,%ebx $1,%eax a at b 5 jge L11 leal (%ebx, %ecx), Xodx 8 L12: inull %eax , %eax addl $1,%ecx addl $1, edx cmp1 %ecx , %ebx 9 10 12 13 J8 14 ·L11: .L12 In generating this code, occ makes an...