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When benzene C6H6 reacts with bromine Br2, bromobenzene C6H5Br is obtained: C6H6 + Br2 --> C6H5Br...

When benzene C6H6 reacts with bromine Br2, bromobenzene C6H5Br is obtained: C6H6 + Br2 --> C6H5Br + HBr (balanced already) When 15.0 g of benzene reacts with excess Br2, 0.19 mole of bromobenzene C6H5Br was produced? IF the actual yield was 42.3 g of C6H5Br produced, Calculate the percent yield.

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When benzene C6H6 reacts with bromine Br2, bromobenzene C6H5Br is obtained: C6H6 + Br2 --> C6H5Br...
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