5.What is Le-Chateliers principle? Discuss the application of this principle on Haber process of synthesis of...
Homework Answers
5. Le-Chateliers principle describes the effect of change in concentration, pressure and temperature on a reversible system. if the system at equilibrium is subjected to a change of concentration or temperature or pressure, the system adjusts itself in such a way that the effect of these changes can be neglected or minimized.
Haber's Process is the process of synthesis of ammonia.The reaction takes place at high pressure and low temperature. From the reaction it is also clear that the reaction is exothermic in nature and release large amount of energy.
N2 + 3H2 
2NH3
+ 22400 Cal
If we discuss Le-Chateliers principle application in this reaction, than to move reaction forward following conditions must be followed:-
Low temperature
High pressure
Higher concentration of H2 and N2
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5.What is Le-Chateliers principle? Discuss the application of
this principle on Haber process of synthesis of...
Review I Constants Periodic Table The common-ion effect is an application of Le Châtelier's principle, which...
Review I Constants Periodic Table The common-ion effect is an application of Le Châtelier's principle, which states that an equilibrium system that is stressed will work to alleviate that stress and reestablish equilibrium. Part B-Calculate the molar solubility in NaOH Based on the given value of the Ksp, what is the molar solubility of Mg(OH)2 in 0.190 M NaOH? Express your answer with the appropriate units. View Available Hint(s) molar solubilityValue Units Submit X Incorrect; Try Again Part C Complete...
1) Ammonia is produced using the Haber process: 3 H2 + N2 2 ---> NH3. Calculate...
1) Ammonia is produced using the Haber process: 3 H2 + N2 2 ---> NH3. Calculate the mass of ammonia produced when 35.0 g of nitrogen react with 12.5 g of hydrogen. 2) Ammonia is produced using the Haber process: 3 H2+ N2 ---> 2 NH3 What percent yield of ammonia is produced from 15.0 kg each of H2and N2, if 13.7 kg of product are recovered? Assume the reaction goes to completion. 3)Sulfuric acid is found in some types of...
the equilibrium concentrations of H2, I2 and HI. 2. Consider the Haber Process for the synthesis of ammonia from hyd...
the equilibrium concentrations of H2, I2 and HI. 2. Consider the Haber Process for the synthesis of ammonia from hydrogen and nitrogen: 3 H2(g) + N2(g) 2 NH3(g) Show that the reaction would shift to the right if the pressure is doubled. 3. a) How would you drive the following reaction to the right to form more products: CO(g) + H20 (g) CO2(g) + H2 (g) AH°= -40.3 kJ Ans.: b) One of the products is a 'high value substance....
1) Write the solubility-product expression for the following mercury salts: Hg2Cl2 and HgCl2. 2) Exactly 0.133...
1) Write the solubility-product expression for the following mercury salts: Hg2Cl2 and HgCl2. 2) Exactly 0.133 mg of AgBr will dissolve in 1.00 L of water. What is the value of Ksp for AgBr? 3) By experiment, it is found that 1.2 x 10-3 mol of lead (II) iodide, PbI2, dissolves in 1.0 L of water at 25°C. What is the Ksp at this temperature? 4) What is the molar solubility of silver chloride in 1.0 L of solution that...
T-pentyl Chloride Lab 1. Define Le Chatilier’s principle, and describe how it applies to the synthesis...
T-pentyl Chloride Lab
1. Define Le Chatilier’s principle, and describe how it applies
to the synthesis of t-pentyl chloride in concentrated HCl,
or the conversion of t-pentyl chloride to
t-pentyl alcohol during the aqueous extraction.
2. When doing boiling point determination with a capillary tube
and boiling bell, what is the gas that is appearing in slow bubbles
when t-pentyl chloride is heated to 70 °C?
3. When doing boiling point determination with a capillary tube
and boiling bell, what...
What is the molar solubility, x, of Ba3(PO4)2 in terms of Ksp? Ba3(PO4)2 (s) – 3...
What is the molar solubility, x, of Ba3(PO4)2 in terms of Ksp? Ba3(PO4)2 (s) – 3 Ba2+ (aq) + 2 PO43- (aq) K sp, 115 A. x = (som B. x = [Ksp]1/2 Кsp 108 C. X = 6 -)1/5 OD. X = Ksp 1/5
Learning Goal: To understand the relationship between precipitation and the solubility product and to be able...
Learning Goal: To understand the relationship between precipitation and the solubility product and to be able to predict whether a substance will precipitate or not. Precipitation is the formation of an insoluble substance. For the equation AB(s)⇌A+(aq)+B−(aq), precipitation represents a shift to the left and the production of a solid. From Le Châtelier's principle, we know that when the product of the concentrations of A+ and B− gets above a certain level, the reaction will respond by shifting left to...
Problem #1: Haber-Bosch process. The Haber-Bosch process is an equilibrium-limited catalyzed reaction that converts nitrogen (N2)...
Problem #1: Haber-Bosch process. The Haber-Bosch process is an equilibrium-limited catalyzed reaction that converts nitrogen (N2) and hydrogen (H2) into ammonia (NH3). The process won Haber a Nobel Prize since it provided a way to produce fertilizer for millions of people at the beginning of the 20th century. However, this process typically has very low single pass conversion due to a low equilibrium at the prevailing temperature and therefore a recycle stream is required to achieve a high overall conversion....
It's part k and calculation 0.4067×0.4067=0.165 also I dont understand questions 1-4 k. Calculate the Ksp...
It's part k and calculation 0.4067×0.4067=0.165
also I dont understand questions 1-4
k. Calculate the Ksp of KHP in 0.5 M KCl solution. Is there a difference between the Ksp in 0.5 M KCl and the Ksp in purified water (calculation d)? [K] = [HP] = - Calculation Ksp = D=0.165 4a. Look up the Ksp for Mn(OH)2 and provide the reference: 1.6 X10 reference: /.6 X10-13 Reference b. The pH of a saturated solution of Mn(OH)2 is 9.90. Calculate...
Learning Goal: To understand the relationship between precipitation and the solubility product and to be able...
Learning Goal: To understand the relationship between precipitation and the solubility product and to be able to predict whether a substance will precipitate or not. Precipitation is the formation of an insoluble substance. For the equation AB(s)⇌A+(aq)+B−(aq), precipitation represents a shift to the left and the production of a solid. From Le Châtelier's principle, we know that when the product of the concentrations of A+ and B− gets above a certain level, the reaction will respond by shifting left to...
Review I Constants Periodic Table The common-ion effect is an application of Le Châtelier's principle, which states that an equilibrium system that is stressed will work to alleviate that stress and reestablish equilibrium. Part B-Calculate the molar solubility in NaOH Based on the given value of the Ksp, what is the molar solubility of Mg(OH)2 in 0.190 M NaOH? Express your answer with the appropriate units. View Available Hint(s) molar solubilityValue Units Submit X Incorrect; Try Again Part C Complete...
the equilibrium concentrations of H2, I2 and HI. 2. Consider the Haber Process for the synthesis of ammonia from hydrogen and nitrogen: 3 H2(g) + N2(g) 2 NH3(g) Show that the reaction would shift to the right if the pressure is doubled. 3. a) How would you drive the following reaction to the right to form more products: CO(g) + H20 (g) CO2(g) + H2 (g) AH°= -40.3 kJ Ans.: b) One of the products is a 'high value substance....
T-pentyl Chloride Lab
1. Define Le Chatilier’s principle, and describe how it applies
to the synthesis of t-pentyl chloride in concentrated HCl,
or the conversion of t-pentyl chloride to
t-pentyl alcohol during the aqueous extraction.
2. When doing boiling point determination with a capillary tube
and boiling bell, what is the gas that is appearing in slow bubbles
when t-pentyl chloride is heated to 70 °C?
3. When doing boiling point determination with a capillary tube
and boiling bell, what...
What is the molar solubility, x, of Ba3(PO4)2 in terms of Ksp? Ba3(PO4)2 (s) – 3 Ba2+ (aq) + 2 PO43- (aq) K sp, 115 A. x = (som B. x = [Ksp]1/2 Кsp 108 C. X = 6 -)1/5 OD. X = Ksp 1/5
It's part k and calculation 0.4067×0.4067=0.165
also I dont understand questions 1-4
k. Calculate the Ksp of KHP in 0.5 M KCl solution. Is there a difference between the Ksp in 0.5 M KCl and the Ksp in purified water (calculation d)? [K] = [HP] = - Calculation Ksp = D=0.165 4a. Look up the Ksp for Mn(OH)2 and provide the reference: 1.6 X10 reference: /.6 X10-13 Reference b. The pH of a saturated solution of Mn(OH)2 is 9.90. Calculate...
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