Person A owns three pairs of pants and twelve shirts. In how many ways can this person pack two pairs of pants and four shirts for a weekend trip?
Number of ways to select r items from n, nCr = n!/(r! x (n-r)!)
Number of pants = 3
Number of ways to select 2 pants = 3C2
= 3!/(2! x 1!)
= 3
Number of shirts = 12
Number of ways to select 4 shirts = 12C4
= 12!/(4! x 8!)
= 495
Number of ways to pack two pairs of pants and four shirts for a weekend trip = Number of ways to select 2 pants x Number of ways to select 4 shirts
= 3 x 495
= 1485
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