Question

Your assignment:

Write a program that takes a number from the command line in the program C.

It should print:

The number.

The number of bits in the number that are set to 0 and 1.

Answer 1

Dear Student,

below i have written the complete C program as per the requirement.

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Program:

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#include<stdio.h>

#include<string.h>

#include<stdlib.h>

int main(int argc, char *argv[])

{

   //variable declaration

   int ones = 0;
   int zeros = 0;

   char *num = (char*)malloc(100*sizeof(char));

   printf("The number is: %s\n",argv[1]);

   //copy the argv[1] to num variable upto its length

   strncpy(num, argv[1], strlen(argv[1]));

   //if number of arguments passed are less than 2 then print usage message

   if(argc < 2)

   {

       printf("Usage .filename number\n");

       return 1;

   }

   //loop through num until null char occurs

   while(*num != '\0')
   {

       //if char is zero then increment count of zeros by 1
       if(*num=='0')
       {
           zeros++;
       }
       //if char is one then increment count of ones by 1
       if(*num=='1')
       {
           ones++;
       }
       *num++;

   }

   //display the zeros and ones

   printf("number of Bits set to zero = %d\n", zeros);

   printf("number of Bits set to one = %d\n", ones);

   return 0;

}

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Sample Output:

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Kindly Check and Verify Thanks...!!!