Question

Determine the value of n in the Nernst equation for the following reactions: CH4(g) + 2...

  1. Determine the value of n in the Nernst equation for the following reactions:

    CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(l)

    2 NO3-(aq) + 4 H+(aq) + Cu+(aq) → 2 NO2(g) + 2 H2O(l) + Cu2+(aq)
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Answer #1

(1) CH4 (g) + 2 O2 (g) CO2 (g) + 2 H2O (l)

Oxidation number of carbon in CH4 is -4

Oxidation number of carbon in CO2 is +4

change in oxidation number for carbon = final oxidation number - initial oxidation number

change in oxidation number for carbon = +4 - (-4)

change in oxidation number for carbon = 4 + 4

change in oxidation number for carbon = 8

Value of n is 8

(2) 2 NO3- (aq) + 4 H+ (aq) + Cu (aq) 2 NO2 (g) + 2 H2O (l) + Cu2+ (aq)

Oxidation number of copper in Cu is 0

Oxidation number of copper in Cu2+ is +2

change in oxidation number for copper = final oxidation number - initial oxidation number

change in oxidation number for copper = +2 - (0)

change in oxidation number for copper = 2

Value of n is 2

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