Question

10 ml of a hydrocarbon was mixed with 70 ml of oxygen (excess) and sparked. The...

10 ml of a hydrocarbon was mixed with 70 ml of oxygen (excess) and sparked. The volume after explosion was 55 ml, and this was reduced to 35 ml by treatment with KOH solution. All volumes are measured at the same temperature and pressure. Deduce the molecular formula of the gas.

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
10 ml of a hydrocarbon was mixed with 70 ml of oxygen (excess) and sparked. The...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 15. The molecular formula of a gaseous hydrocarbon can be determined by combusting it completely in...

    15. The molecular formula of a gaseous hydrocarbon can be determined by combusting it completely in excess oxygen and then passing it through potassium hydroxide solution to absorb the carbon dioxide produced. In an experiment 200 cm' of a hydrocarbon was reacted with 1500 cm of oxygen. After the hydrocarbon had combusted completely 1000 cm of gas remained. This volume was reduced to 200 cm3 after the gas had been passed through a solution of potassium hydroxide. All volumes were...

  • 10.0 cm3 of a gaseous hydrocarbon X were exploded with 100.0 cm^3 of oxygen (an excess). After cooling, the total volume of the gaseous mixture was 80.0 cm^3 . After treatment with KOH (aq), the volum...

    10.0 cm3 of a gaseous hydrocarbon X were exploded with 100.0 cm^3 of oxygen (an excess). After cooling, the total volume of the gaseous mixture was 80.0 cm^3 . After treatment with KOH (aq), the volume of gas decreased to 40.0 cm^3 . All volumes were measured at the same temperature and pressure. Use this information to determine the molecular formula of X. Draw two possible structures for X.

  • Under STP conditions, 100.0 mL of an unknown hydrocarbon gas was combusted in excess oxygen. The...

    Under STP conditions, 100.0 mL of an unknown hydrocarbon gas was combusted in excess oxygen. The only products of the combustion were 300.0 mL of carbon dioxide and 400.0 mL of water vapor. a. What are the intermolecular forces common to hydrocarbon gases? b. Does the behavior of these gases tend to resemble ideal gas behavior? How might these gases be expected to deviate from this behavior? c. How many moles of carbon dioxide are produced in the combustion? d....

  • 1 A pure hydrocarbon is used in bottled gas for cooking and heating. When 10 cm...

    1 A pure hydrocarbon is used in bottled gas for cooking and heating. When 10 cm of the hydrocarbon is burned in 70 cm of oxygen (an excess), the final gaseous mixture contains 30 cm of carbon dioxide and 20 cm of unreacted oxygen. All gaseous volumes were measured under identical conditions. What is the formula of the hydrocarbon? A C₂Ho B CaHo c Cato Chio 2 On collision, airbags in cars inflate rapidly due to the production of nitrogen....

  • A 50.0-ml sample of a 1.00 m solution of cuso4 is mixed with 50.0 ml of...

    A 50.0-ml sample of a 1.00 m solution of cuso4 is mixed with 50.0 ml of 2.00 M KOH in a calorimeter. the temperature of both solutions was 20.2C before mixing and 26.3C after mixing. The heat capacity of the calorimeter is 12.1 J/k. from these data calculate ΔH for the process: CuSO4 (1M) +2KOH (2M)---->Cu(OH)2 (s) + K2SO4 (0.5M) Assume the specific heat and density of the solution after mixing are the same as those of pure water and...

  • A 100.00 mL volume of 0.500 M HCl was mixed with 100.00 mL of 0.500 M KOH in a constant pressure calorimeter. The initi...

    A 100.00 mL volume of 0.500 M HCl was mixed with 100.00 mL of 0.500 M KOH in a constant pressure calorimeter. The initial tem- perature of the individual HCl and KOH solu- tions was 22.50°C. The final temperature of the solution after mixing was 25.80°C. The density of the solution was 1.02 g/mL. The specific heat of the solution was 3.97J•gl. degree-l. Identify the system and the surroundings. What gained heat? What lost heat? How much heat was gained...

  • a)  A 50.0 mL sample of a 1.00 M solution of CuSO4 is mixed with 50.0 mL...

    a)  A 50.0 mL sample of a 1.00 M solution of CuSO4 is mixed with 50.0 mL of 2.00 M KOH in a calorimeter. The temperature of both solutions was 18.1 oC  before mixing and 39.1 oC  after mixing. The heat capacity of the calorimeter is 12.1 J/K.  From these data, calculate ΔH for the process: CuSO4(1M)+ 2KOH(2M) →Cu(OH)2(s) + K2SO4(0.5M) Assume that the specific heat and density of the solution after mixing are the same as those of pure water and that the...

  • A 50 ml sample of a 1.0 M solution of CuSO4 is mixed with 50 mL...

    A 50 ml sample of a 1.0 M solution of CuSO4 is mixed with 50 mL of 2.0 M KOH in a calorimeter. The temperature of both solutions was 23.9°C before mixing and 33.5°C ofter mixing. The heat capacity of the calorimeter is 12.1 J/K. From these data, calculate AH for the process: CuSO4 (1M) + 2KOH (2M) - Cu(OH)2 (8) + K2504 (0.5M) Assume that the specific heat and density of the solution after mixing are the same as...

  • A 50.0 mL sample of a 1.00 M solution of CuSO4 is mixed with 50.0 mL...

    A 50.0 mL sample of a 1.00 M solution of CuSO4 is mixed with 50.0 mL of 2.00 M KOH in a calorimeter. The temperature of both solutions was 20.3°C before mixing and 31.7 °C after mixing. The heat capacity of the calorimeter is 12.1 J/K. From these data, calculate AH for the process: CuSO4(1M) + 2KOH(2M) +Cu(OH)2 (s) + K2SO4(0.5M) Assume that the specific heat and density of the solution after mixing are the same as those of pure...

  • A sample of oxygen gas has a volume of 545 mL at 35 degree C. The...

    7. A sample of oxygen gas has a volume of 545 mL at 35 degree C. The gas is heated to 151 degree C at constant pressure in a container that can contract or expand. What is the final volume of the oxygen gas?  A) 750 mL  B) 396 mL  C) 417 mL  D) 267 mL  E) 126 mL  8. A 45 mL sample of nitrogen gas is cooled from 135 degree C to 15 degree C in a container...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT