c) public class Test { public static void main(String[] args) { T t1 = new T();...
c) public class Test { public static void main(String[] args) { T t1 = new T(); T t2 = new T(); System.out.println("t1's i = " + t1.i + " and j = " + t1.j); System.out.println("t2's i = " + t2.i + " and j = " + t2.j); } } class T { static int i = 0; int j = 0; T() { i++; j = 1; } }
Why is t1's i = 2 ? It should be one since the first no arg consturctor makes it 1. initally it's 0
Homework Answers
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c) public class Test { public static void main(String[] args) {
T t1 = new T();...
import java.util.Scanner; public class TriangleMaker { public static void main(String[] args) { //...
import java.util.Scanner; public class TriangleMaker { public static void main(String[] args) { // TODO Auto-generated method stub System.out.println("Welcome to the Triangle Maker! Enter the size of the triangle."); Scanner keyboard = new Scanner(System.in); int size = keyboard.nextInt(); for (int i = 1; i <= size; i++) { for (int j = 0; j < i; j++) { System.out.print("*"); } System.out.println(); } for (int...
1. Analyze the following code: public class Test implements Runnable { public static void main(String[] args) { Thread t = new Thread(this); t.start(); } public void run() { System....
1. Analyze the following code: public class Test implements Runnable { public static void main(String[] args) { Thread t = new Thread(this); t.start(); } public void run() { System.out.println("test"); } } 1. The code compiles but will not print anything since t does not invoke the run method. 2. The code will not compile since you cannot invoke "this" in a static method. 3. The program compiles, runs, and prints tests on the console. 2. What will the following example...
Analyze the following code: public class Test { private int t; public static void main(String[] args)...
Analyze the following code: public class Test { private int t; public static void main(String[] args) { int x; System.out.println(t); } } t is non-static and it cannot be referenced in a static context in the main method. The program compiles and runs fine. The variable t is not initialized and therefore causes errors. The variable x is not initialized and therefore causes errors.
Analyze the following code: public class Test { private int t; public static void main(String[] args)...
Analyze the following code: public class Test { private int t; public static void main(String[] args) { int x; System.out.println(t); } } The variable t is private and therefore cannot be accessed in the main method. The program compiles and runs fine. t is non-static and it cannot be referenced in a static context in the main method. The variablet is not initialized and therefore causes errors. The variable x is not initialized and therefore causes errors.
Review the following code: public class Looping { public static void main(String[] args) { ...
Review the following code: public class Looping { public static void main(String[] args) { for (int i = 1; i <= 5; i++) { for (int j = 1; j <= 5; j++) { System.out.println(i + " x " + j + " = " + (i * j)); } } } } What is the output from the code above? Replace this text with your solution What happens if you change the...
class Test public static void main(String args) { Aa=new AO: a.printo: class A private String s;...
class Test public static void main(String args) { Aa=new AO: a.printo: class A private String s; public A (String news) { 8 = news: public void print { System.out.println(s): The program would compile and run if you change A a new Alto Aa=new A('5'). The program has a compilation error because the instance variables in class A is not public. The program has a compilation error because class A does not have a no-arguments constructor The program compiles and runs...
What are the errors in this ? public class Mystery { public static void main(String[] args)...
What are the errors in this ? public class Mystery { public static void main(String[] args) { double initialSavings = 10000; double interestRate = 0.05; double currSavings = 0; int i; System.out.println("\nAnnual savings 5 years: "); currSavings = initialSavings; for (i = 0, i < 5, ++i); currSavings = (currSavings * interestRate); System.out.println("$" + currSavings); } }
Consider the following codes: public class TestThread extends Thread { public static void main(String[] args)...
Consider the following codes: public class TestThread extends Thread { public static void main(String[] args) { TestThread thread = new TestThread(); } @Override public void run() { printMyName(); } private void printMyName() { System.out.println("Thread is running"); } } Test Stem / Question Choices 1: What method should you invoke to start the thread TestThread? A: start() B: run() C: No. Thread will run automatically when executed. D: TestThread is not...
What is wrong the following code? Explain. public class Test { public static void main(String[] args)...
What is wrong the following code? Explain. public class Test { public static void main(String[] args) { A a = new A(5.0); } class A { int value = 2; } }
import java.util.Scanner; public class Client{ public static void main(String args[]){ Coin quarter = new Coin(25);...
import java.util.Scanner; public class Client{ public static void main(String args[]){ Coin quarter = new Coin(25); Coin dime = new Coin(10); Coin nickel = new Coin(5); Scanner keyboard = new Scanner(System.in); int i = 0; int total = 0; while(true){ i++; System.out.println("Round " + i + ": "); quarter.toss(); System.out.println("Quarter is " + quarter.getSideUp()); if(quarter.getSideUp() == "HEADS") total = total + quarter.getValue(); dime.toss(); System.out.println("Dime is " + dime.getSideUp()); if(dime.getSideUp() == "HEADS") total = total +...
Analyze the following code: public class Test { private int t; public static void main(String[] args) { int x; System.out.println(t); } } t is non-static and it cannot be referenced in a static context in the main method. The program compiles and runs fine. The variable t is not initialized and therefore causes errors. The variable x is not initialized and therefore causes errors.
Analyze the following code: public class Test { private int t; public static void main(String[] args) { int x; System.out.println(t); } } The variable t is private and therefore cannot be accessed in the main method. The program compiles and runs fine. t is non-static and it cannot be referenced in a static context in the main method. The variablet is not initialized and therefore causes errors. The variable x is not initialized and therefore causes errors.
class Test public static void main(String args) { Aa=new AO: a.printo: class A private String s; public A (String news) { 8 = news: public void print { System.out.println(s): The program would compile and run if you change A a new Alto Aa=new A('5'). The program has a compilation error because the instance variables in class A is not public. The program has a compilation error because class A does not have a no-arguments constructor The program compiles and runs...
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