The plates of a parallel-plate capacitor are 3.50 mm apart, and each carries a charge of magnitude 85.0 nC . The plates are in vacuum. The electric field between the plates has a magnitude of 5.00×106 V/m .
Part A: What is the potential difference between the plates?
Part B:What is the area of each plate?
Part C:What is the capacitance?
The plates of a parallel-plate capacitor are 3.50 mm apart, and each carries a charge of...
w2.18.30 The plates of a parallel-plate capacitor are 3.00 mmapart, and each carries a charge of magnitude 85.0 nC. The plates are in vacuum. The electric field between the plates has a magnitude of 5.00×106V/m. Part A: What is the potential difference between the plates? Part B: What is the area of each plate? Part C: What is the capacitance?
Problem 18.30 What is the potential difference between the plates? The plates of a parallel-plate capacitor are 350 mm apart, and each carries a charge of magnitude 81.0 nC. The plates are in vacuum. The electric field between the plates has a magnitude of 3.00*10° V/m Submit ▼ Part B What is the area of each plate? A- Submit PartC What is the capacitance?
The plates of a parallel-plate capacitor in vacuum are 2.90 mm apart and 2.75 m^2 in area. When you apply a certain potential difference across the capacitor, the surface charge density on the positive plate is 1.40×10−5C/m^2. Calculate the capacitance of the capacitor. C = Find the potential difference. V =
A parallel-plate air capacitor has a capacitance of 300 pF and a charge of magnitude 0.150 μC on each plate. The plates are 0.500 mm apart. A. What is the potential difference between the plates? Answer: V=500V B. What is the area of each plate? C. What is the electric-field magnitude between the plates? D. What is the surface charge density on each plate?
A capacitor has parallel plates that have an area of 1.09 cm2 and are 1.08 mm apart. There is a vacuum between the plates, and the electric field magnitude is 1.10 106 N/C. (a) Find the potential across the plates. (b) Find the charge.
A parallel-plate air-filled capacitor having area 31 cm2 and plate spacing 3.0 mm is charged to a potential difference of 400 V. Find the following values. (a) the capacitance pF (b) the magnitude of the charge on each plate nC (c) the stored energy μJ (d) the electric field between the plates V/m (e) the energy density between the plates J/m3
A parallel-plate air-filled capacitor having area 44 cm2 and plate spacing 5.0 mm is charged to a potential difference of 850 V. Find the following values. (a) the capacitance (pF) (b) the magnitude of the charge on each plate (nC) (c) the stored energy (μJ) (d) the electric field between the plates (V/m) (e) the energy density between the plates (J/m3)
The plates of a parallel-plate capacitor are 700 cm2 in area and 0.3 cm apart. The potential difference between the plates is 935 V. (a) What is the magnitude of the electric field between the plates? (b) the charge on each plate? (c) the force exerted by the field on one of the plates? Now the two plates touch at the bottom forming a V-shape. (d) Find the total electric energy stored between the plates.
1) The plates of a parallel-plate capacitor are 700 cm2 in area and 0.3 cm apart. The potential difference between the plates is 935 V. (a) What is the magnitude of the electric field between the plates? (b) the charge on each plate? (c) the force exerted by the field on one of the plates? Now the two plates touch at the bottom forming a V-shape. (d) Find the total electric energy stored between the plates.
A parallel-plate capacitor has a plate area of A = 250 cm2 and a separation of d = 2.00 mm. The capacitor is charged to a potential difference of V0 = 150 V by a battery. A dielectric sheet (κ = 3.50) of the same area but thickness ℓ = 1.00 mm is placed between the plates without disconnecting the battery. (See figure 24-18 on page 642). Determine the initial capacitance of the air-filled capacitor. Determine the charge on the...