Question

1. How much heat will be lost by 20 g of steam at 108 oC to transform into 20 g of water at 31 oC.

(cice= 2.05 kJ/kg, cwater=4.18 kJ*K/kg, csteam=2.01 kJ*K/kg; Lfwater=333.5 kJ/kg @ 0 oC, Lvwater= 2257 kJ/kg @100 oC)

Q= J

2. A 60 g mass of copper at 960 oC is dropped into 325 g of water at 20 oC and allowed to come to thermal equilibrium. What will the final temperature be?

(cice= 2.05 kJ/kg, cwater=4.18 kJ*K/kg, csteam=2.01 kJ*K/kg; Lfwater=333.5 kJ/kg @ 0 oC, Lvwater= 2257 kJ/kg @100 oC)

(ccopper= 0.386 kJ/kg, Lfwater=205 kJ/kg @ 1356 oC)

T= oC

Answer 1