16. Fifty-eight percent of all adults plan to purchase a Fitbit next year. You randomly select 200 adults and ask them if they plan to buy a Fitbit next year. What is the probability that at least 120 of these adults will say they will buy a Fitbit next year?
Mean = np = 0.58 * 200 = 116
Standard deviation = sqrt( np(1-p))
= sqrt ( 200 * 0.58 * 0.42)
= 6.98
Using normal approximation ,
P( X >= x) = P( Z > x-0.5 - mean / SD)
So,
P( X >= 120) = P( Z > 119.5 - 116 / 6.98)
= P( Z > 0.5014)
= 0.3080
16. Fifty-eight percent of all adults plan to purchase a Fitbit next year. You randomly select...
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