Question

PLEASE DO THIS IN RUBY

# Write a method bigger_filter that accepts an array of numbers and a target number. The method should return a new array containing the elements that are greater than the given target.

def bigger_filter(arr, tar)
end

print bigger_filter([7,3,2,8,12], 5) # => [7, 8, 12]
#puts
print bigger_filter([1,2,3], 100) # => []
#puts
print bigger_filter([10,9,20,3], 9) # => [10, 20]

MY ATTEMPT

def bigger_filter(arr, tar)
   new_arr = []

   i = 0
   while i < tar
       old_arr = arr[i]
       if old_arr > tar
           new_arr << old_arr
       else old_arr < tar
       end

       i += 1
   end

   return new_arr
end

It only works with the first line of code but not the other 2 because it gives me an error regarding Syntax.

Answer 1

Hi,

Please find the answer below:

The bug is the while loop: Your condition should be i less than array length.

while i < arr.length

and NOT while i < tar

Also, i have removed unnecessary usage of the variable in the loop.

Steps

• Just simplified your logic using Array.new()
• Iterate over the input array.
• If the condition is met push to new array.
• return the new array

Fixed Code:

def bigger_filter(arr, tar)
   new_arr = []

   i = 0
   while i < arr.length
       if arr[i] > tar
           new_arr << arr[i]
       end

       i += 1
   end

   return new_arr
end

print bigger_filter([10,9,20,3], 9) # => [10, 20]

Screenshot:

-----------------------------------------------

Like the solution if you find it useful.

Hope this helps.