Question

Multiples of 9’s (JAVA)

Using the logic behind the algorithm in Part 1, it’s easy to calculate the first nine multiples of 9 (9x1, 9x2, 9x3…, 9x9).

Let’s use two examples. First, to determine the product of 9 times 6, perform the following algorithm:

Step 1: Subtract 1 from the number being multiplied by 9 (in this case 6) to get the first digit of the product: 6 – 1 =  5.
Step 2: Subtract that digit from 9 to get the second digit: 9 – 5 = 4.
Result: Put the two digits together to get the answer:  54

To determine the product of 9 times 3, perform the following:

Step 1: Subtract 1 from the number being multiplied by 9 (in this case 3) to get the first digit of the product: 3 – 1 =  2.
Step 2: Subtract that digit from 9 to get the second digit: 9 – 2 = 7.
Result: Put the two digits together to get the answer:  27

Using the pattern described in the above two examples, write a program which prompts for and reads an int between 0 and 9 from the user, then calculates and displays that number multiplied by 9. The program then loops back and asks for another number from the user.

Please note that the number 0 may require some special programming, as the above algorithm may not work properly.

Your program should handle any number entered by the user.

• If the user enters the number -1 (the sentinel), then exit the program.
• If the user enters a number between 0 to 9, first determine number multiplied by 9 as described above, then go back to the top of the program to prompt for the next number. (The number 0 may require some special processing).
• Otherwise print an error message telling the user that the number is too large or small, then loop back and prompt for the next number.

Submit all Java programfiles, along with PrintScreens showing the results of entering the following numbers: 0, 3, 6, 9, 10, and the sentinel -1.

Answer 1

Code

import java.util.Scanner;

public class Mian {

/**
* @param args the command line arguments
*/
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int num,a,b,ans;
while(true)
{
System.out.print("Enter a number between 0 - 9 or -1 to stop: ");
num=sc.nextInt();
  
if(num==-1)
break;
if(num>=0 && num<=9)
{
a=num-1;
b=9-a;
ans=a*10+b;
System.out.println("The product of 9 times "+ num +" is "+ans);
}
else
{
System.out.println("Invalid input. Please enter the number between 0 and 9 inclusive.");
}
System.out.println();
}
}
  
}

Output

If you have any query regarding the code please ask me in the comment i am here for help you. Please do not direct thumbs down just ask if you have any query. And if you like my work then please appreciates with up vote. Thank You.