Vector A = an acceleration of 4 m/s/s due east Vector B = an acceleration of...

Question

Question

Vector A = an acceleration of 4 m/s/s due east

Vector B = an acceleration of 3 m/s/s at 40⁰ north of east

Find the magnitude and direction of the vector sum A+B. Include the drawing of the vectors

Answer 1

Answer #1

|A| = 4 m/s^2

|B| = 3 m/s^2

|A + B| = sqrt(4^2 + 3^2 + 2 x 4 x 3 x cos(40)) = 6.58 m/s^2

B)

Tan(theta) = (3 sin(40))/(4 + 3 cos(40)) = 0.306

Theta = arctan (0.306) = 17.02° with A

Comment in case any doubt please rate my answer....

Answer 2

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