mu = 90, sigma = 1.5
how large should the sample size be, to detect a shift in mu to 91?
Answer)
Margin of error = 91 - 90 = 1
Given population s.d = 1.5
As the population s.d is known here we can use z table to estimate the sample size
Here you forgot to mention confidence level
So i will solve for three confidence levels then you can match with your mentioned confidence level
For 90% confidence level (0.90)
Critical value z from z table is 1.645
Margin of error = z*s.d/√n
1 = 1.645*1.5/√n
N = 7
For 95% confidence level (0.95)
Critical value is 1.96
1 = 1.96*1.5/√n
N = 9
For 99% confidence level (0.99)
Critical value is 2.58
N = 15
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