Suppose we put two sets of billiard balls in an urn and randomly draw out 4...

Question

Question

Suppose we put two sets of billiard balls in an urn and randomly draw out 4 balls. What is the probability we get 4 distinct numbers?

Answer 1

Answer #1

Total 30 balls( set of 15 balls)

We are free to select 1st ball

Then for the second draw, the probability of drawing a different ball from the first ball is 28/29

29 as 30-1 balls in urn now(after drawing 1st ball) and only 1 ball is similar to 1st ball so 28/29

On the third draw,

probability of selecting unique is 26/28.

The probability of the fourth being unique, given that the first 3 are distinct, is 24/27

Answer 2

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