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The standard enthalpy change for the following reaction is 641 kJ at 298 K. MgCl2(s) Mg(s)...

The standard enthalpy change for the following reaction is 641 kJ at 298 K. MgCl2(s) Mg(s) + Cl2(g) ΔH° = 641 kJ What is the standard enthalpy change for this reaction at 298 K? Mg(s) + Cl2(g) MgCl2(s)

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Answer #1

As the reaction is reversed in direction the value of enthalpy changes its sign from positive to negative

So the value of ∆H will be -641 KJ

This is according to hess law

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