The standard enthalpy change for the following reaction is 641 kJ at 298 K. MgCl2(s) Mg(s) + Cl2(g) ΔH° = 641 kJ What is the standard enthalpy change for this reaction at 298 K? Mg(s) + Cl2(g) MgCl2(s)
As the reaction is reversed in direction the value of enthalpy changes its sign from positive to negative
So the value of ∆H will be -641 KJ
This is according to hess law
The standard enthalpy change for the following reaction is 641 kJ at 298 K. MgCl2(s) Mg(s)...
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