Question

Java ; Given two Strings, return true if the shorter of the two Strings appears at the very end of the other string, ignoring upper/lower case differences and false otherwise

Answer 1

Solution:

import java.util.Scanner;

public class Sample {
    public static void main(String args[]) {
        String s1, s2;

        Scanner in = new Scanner(System.in);
        System.out.println("Enter string 1:");
        s1 = in.nextLine();
        System.out.println("Enter string 2:");
        s2 = in.nextLine();
        if (Strings(s1, s2)) {
            System.out.println("The longer string ends with shorter string");
        } else
            System.out.println("The longer string does not end with shorter string");
    }

    public static boolean Strings(String s1, String s2) {
        if (s1.length() >= s2.length()) {
            s1=s1.toLowerCase();
            s2=s2.toLowerCase();
            if (s1.endsWith(s2))
                return true;
            else
                return false;
        } else {
            s1=s1.toLowerCase();
            s2=s2.toLowerCase();
            System.out.println(s1);
            System.out.println(s2);
            if (s2.endsWith(s1))
                return true;
            else
                return false;
        }
    }
}

Output: