If 4.12 L of a 0.850M-H3PO4solution is be diluted to a volume of 10.00 L, what...

Question

Question

If 4.12 L of a 0.850M-H3PO4solution is be diluted to a volume of 10.00 L, what is the concentration of theresulting solution

can anyone explain the steps?

Answer 1

Answer #1

Mole before dilution = mole after dilution.

Mole = molarity × volume (L)

Initally mole of H3PO4 = 0.850(mol/L) × 4.12 (L) = 3.502 mole

This mole.will remain constant after the dilution

So molarity ( concentration) = mole / volume =

=3.502 (mole ) / 10 (L)

= 0.3502 M

Answer 2

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