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In a survey, 29 people were asked how much they spent on their child's last birthday...

In a survey, 29 people were asked how much they spent on their child's last birthday gift. The results were roughly shaped as a normal curve with a mean of $30 and standard deviation of $8. Find the margin of error at a 90% confidence level.

Give your answer to two decimal places.

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Answer #1

Number of people surveyed n=29

Sample standard deviation s=8

Confidence level = 90% so =0.10

Formula for margin of error is given by E = ​​​​​​ × s/

Where ​ = 1.701 from t- table at 90% confidence

Therefore E= 1.701× 8/​​​​​ = 2.5269 2.53

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