In a survey, 29 people were asked how much they spent on their
child's last birthday gift. The results were roughly shaped as a
normal curve with a mean of $30 and standard deviation of $8. Find
the margin of error at a 90% confidence level.
Give your answer to two decimal places.
Number of people surveyed n=29
Sample standard deviation s=8
Confidence level = 90% so =0.10
Formula for margin of error is given by E = × s/
Where = 1.701 from t- table at 90% confidence
Therefore E= 1.701× 8/ = 2.5269 2.53
In a survey, 29 people were asked how much they spent on their child's last birthday...
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