1. P( 0 < Z < 2.16 )
= P(z< 2.16) - P(z< 0)
= 0.9846 - 0.5
= 0.4846
2)
P( -1.87 < Z < 0)
= P(z< 0) - P(z< -1.87)
= 0.5 - 0.0307
= 0.4693
3)
. P( -1.63 < Z < 2.17)
= P(z< 2.17) - P(z< -1.63)
= 0.9850 - 0.0516
= 0.9334
4)
P( 1.72 < Z < 1.98)
= P(z< 1.98) - P(z< 1.72)
= 0.9761- 0.9573
= 0.0189
5)
P(z> 1.77)
= 1 - P(z < 1.77)
= 1 -0.9616
= 0.0384
6)
P(z> -1.02)
= 1 - P(z< -1.02)
= 1 - 0.1539
= 0.8461
70
P(z< 2.03)
= 0.9788
Using Standard Normal Distribution, find the posibilitity 1. P( 0 < Z < 2.16 ) 2....
For a standard normal distribution, find: P(-2.43 < z < -1.87) For a standard normal distribution, find: P(-2.43 <z<-1.87) Submit License Question 3. Points possible: 1 This is attempt 1 of 3.
IS Find the following probability for the standard normal random variable z. a. P(z<-1.02) b. P(z <2.03) c. P(0.68 szs2.03) d. P(-2.66szs1.56) a. P(z -1.02)(Round to four decimal places as needed.) b. Pize 2.03)=[] (Round to four decimal places as needed.) ook c. P(0.68 szs2.03) (Round to four decimal places as needed.) d.P(-2.66 s zs 1.56) = [□ (Round to four decimal places as needed.)
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For the standard normal distribution mean = 0 and standard deviation = 1 find: P(z < 2.95) Draw a labeled normal curve
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Standard Normal distribution. With regards to a standard normal distribution complete the following: (a) Find P(Z > 0), the proportion of the standard normal distribution above the z-score of 0. (b) Find P(Z <-0.75), the proportion of the standard normal distribution below the Z-score of -0.75 (c) Find P(-1.15<z <2.04). (d) Find P(Z > -1.25). (e) Find the Z-score corresponding to Pso, the 90th percentile value.
Let z be a random variable with a standard normal distribution. Find P(0 ≤ z ≤ 0.40), and shade the corresponding area under the standard normal curve. (Use 4 decimal places.)
1) Given a standard normal distribution, find the probability of having a z score higher than 1.67 ```{r} ``` 2) Given that test scores for a class are normally distributed with a mean of 80 and variance 36, find the probability that a test score is lower than a 45. ```{r} ``` 3) Given a standard normal distribution, find the Z score associated with a probability of .888 ```{r} ``` 4) Find the Z score associated with the 33rd quantile...
Suppose that Z is the standard normal distribution. Find P(Z<-1.81). Suppose that Z is the standard normal distribution. Find P(Z>2). Suppose that Z is the standard normal distribution. Find P(-1.95<Z<1.07). Suppose that Z is the standard normal distribution. What value of Z represents the 20th percentile?
Find the indicated probability using the standard normal distribution. Find the indicated probability using the standard normal distribution. P(-0.39<z<0) Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. P(-0.39<z<0)= (Round to four decimal places as needed.)