Question

Java Programming

Use a one-dimensional array to solve the following program. Write an application that inputs six numbers [Keep the numbers in an array]. The numbers must be between 20 and 200, inclusive. If the number is not between 20 and 200, ask for another input. When a number is entered, display the number only if it is not a duplicate of a number already entered. If it is a duplicate of a number already entered, display a message that the number is a duplicate number and ask for another input. Provide for the worst case in which all six numbers are different. Display the complete set of unique values input after the user enters each new value. UPLOAD Duplicate.java

Answer 1

import java.util.Scanner;

public class Duplicate {
   public static void main(String[] args) {
       int counter[]=new int[201];
       int arr[]=new int[6];
       int n,count=0;
       Scanner sc = new Scanner(System.in);
       while(true) {
           System.out.println("Enter number between (20-200): ");
           n=sc.nextInt();
           if(n<20 || n>200) {
               System.out.println("Number must be between 20-200. Try again");
               continue;
           }
           if(counter[n]==0) {
               counter[n]=1;
               arr[count++]=n;
           }
           else {
               System.out.println("Value already exist. Try again");
               continue;
           }
           printArray(arr,count);
           if(count==6)
               break;
       }
   }

   private static void printArray(int[] arr, int n) {
       for(int i=0;i<n;i++)
           System.out.print(arr[i]+" ");
       System.out.println();
   }
}

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