Question

Write a program called CountCoins.java that prompts the user for the input file name (you can copy the getInputScanner() method given in the ProcessFile assignment) then reads the file. The file contains a series of pairs of tokens, where each pair begins with an integer and is followed by the type of coin, which will be “pennies” (1 cent each), “nickels” (5 cents each), “dimes” (10 cents each), or “quarters” (25 cents each), case-insensitively. Add up the cash values of all the coins and print the total amount of money. For example, if the input file contains the following text:

3 pennies 2 quarters 1 Pennies 23 NiCkeLs 4 DIMES

For the input above, your method should produce the following output:
Total money: $2.09

Answer 1

import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;

public class CountCoins {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        System.out.print("Enter input file name: ");
        String inName = in.nextLine();
        File file = new File(inName);
        Scanner fin;
        try {
            fin = new Scanner(file);
            double total = 0;
            int n;
            String type;
            while (fin.hasNextInt()) {
                n = fin.nextInt();
                type = fin.next();
                if (type.equalsIgnoreCase("pennies")) {
                    total += n*0.01;
                } else if (type.equalsIgnoreCase("quarters")) {
                    total += n*0.25;
                } else if (type.equalsIgnoreCase("nickels")) {
                    total += n*0.05;
                } else if (type.equalsIgnoreCase("dimes")) {
                    total += n*0.10;
                }
            }
            System.out.printf("Total money: $%.2f\n", total);
            fin.close();
        } catch (FileNotFoundException e) {
            System.out.println(file.getAbsolutePath() + " does not exists!");
        }
    }
}