Question

A network was assigned the address 10.10.64.0/22 by the Internet Service Provider.

What is the subnet Mask of this network (decimal format)?

What is the maximum number of hosts that could be part of this network?

What is the IP address of the 1st host of this network (decimal format)?

What is the IP address of the 2nd host of this network (decimal format)?

What is the broadcast address in this network (Decimal format)?

What is the last IP address that could be assigned to a host (decimal format)?

Answer 1

1)What is the subnet Mask of this network (decimal format)?
answer)
10.10.64.0/22 means 22 bits are assigned to network id portion.
so in subnet mask we need to place 22 ones and 10 zeros.
subnet mask in binary is 11111111.11111111.11111100.00000000
subnet mask in decimal is 255.255.252.0

2)What is the maximum number of hosts that could be part of this network?
answer)
here 10 bits are assigned to host id part so total 2^10 hosts are possible.
here 2^10 -2 are useable host address possible
3)What is the IP address of the 1st host of this network (decimal format)?
answer)
1st ip address of host is 10.10.64.1/22

4)What is the IP address of the 2nd host of this network (decimal format)?
answer)10.10.64.2/22

5)What is the broadcast address in this network (Decimal format)?
answer)convert given ip and inverted subnet mask perform or operation between them
then we get broadcast address.
broadcast address is 10.10.64.255/22
6)What is the last IP address that could be assigned to a host (decimal format)?
answer)
10.10.64.254/22