3. Alcohol (C2H5OH) levels in blood can be determined by a redox titration as follows: C2H5OH...
3. Alcohol (C2H5OH) levels in blood can be determined by a redox titration as follows: C2H5OH (aq) + 2 Cr2O72-(aq) + 16 H+ ----> 2 CO2 (g) + 4 Cr3+(aq) + 11 H2O
(a) How many grams of alcohol are in a blood sample if 8.76 mL of 0.04988M K2Cr2O7 is required for its complete titration?
Suppose the sample of blood in Part (a) weighed 10.002 g, what is the mass % of alcohol in the sample?
Homework Answers
Answer :-
Firstly the balanced chemical equation is written for the alcohol. Then using the given data moles of alcohol is calculated then mass of alcohol is calculated and the mass %.
The answer is given in the image,
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3. Alcohol (C2H5OH) levels in blood can be determined by a redox
titration as follows: C2H5OH...
1 Review | Constants | Periodic Table Alcohol levels in blood can be determined by a...
1 Review | Constants | Periodic Table Alcohol levels in blood can be determined by a redox titration with potassium dichromate according to the balanced equation C2H5OH (aq) + 2Cr2O2 (aq) +16H+ (aq) → 2CO2 (g) + 4Cr3+ (aq) +11H2O (1) Part A What is the blood alcohol level in mass percent if 8.05 mL of 0.04988 M K2Cr2O7 is required for titration of a 10.000 g sample of blood?
A person's blood alcohol (C2H5OH) level can be determined by titrating a sample of blood plasma...
A person's blood alcohol (C2H5OH) level can be determined by titrating a sample of blood plasma with a potassium dichromate solution. The balanced equation is 16H+(aq) + 2Cr2O72−(aq) + C2H5OH(aq) → 4Cr3+(aq) + 2CO2(g) + 11H2O(l) If 35.46 mL of 0.05961 M Cr2O72− is required to titrate 27.30 g of plasma, what is the mass percent of alcohol in the blood?
A person’s blood alcohol (C2H5OH) level can be determined by titrating a sample of blood plasma...
A person’s blood alcohol (C2H5OH) level can be determined by titrating a sample of blood plasma with a potassium dichromate solution. The balanced equation is 16H+ (aq) + 2Cr2O72-‐(aq) + C2H5OH → 4Cr3+(aq) + 2CO2(g) + 11H2O(l) (a) Identify the reducing agent and oxidizing agent. (b) If 45.32 mL of 0.04261 M dichromate ion is required to titrate 25.00 g of the blood plasma, what is the mass percent of alcohol in the blood plasma
Breathalyzers determine the alcohol content in a person's breath by the following (unbalanced) redox reaction: C2H5OH...
Breathalyzers determine the alcohol content in a person's breath by the following (unbalanced) redox reaction: C2H5OH + Cr2O72− → CH3CO2H + Cr3+ (acidic solution) If analysis of a breath sample generates 1.70 x 10-4 M Cr3+ ions in 25.0 mL, how many mg of alcohol did it contain? NOTE: This is a case of balancing the chemical equation correctly, using redox reactions. Once you have the correct stoichiometric ratio between ethanol and Cr3+, as well as the molecular weight of...
Breathalyzers determine the alcohol content in a person's breath by the following (unbalanced) redox reaction: C2H5OH...
Breathalyzers determine the alcohol content in a person's breath by the following (unbalanced) redox reaction: C2H5OH + Cr2O72− → CH3CO2H + Cr3+ (acidic solution) If analysis of a breath sample generates 1.70 x 10-4 M Cr3+ ions in 25.0 mL, how many mg of alcohol did it contain? NOTE: This is a case of balancing the chemical equation correctly, using redox reactions. Once you have the correct stoichiometric ratio between ethanol and Cr3+, as well as the molecular weight of...
Breathalyzers determine the alcohol content in a person's breath by the following (unbalanced) redox reaction: C2H5OH...
Breathalyzers determine the alcohol content in a person's breath by the following (unbalanced) redox reaction: C2H5OH + Cr2O72− → CH3CO2H + Cr3+ (acidic solution) If analysis of a breath sample generates 6.80 x 10-4 M Cr3+ ions in 75.0 mL, how many mg of alcohol did it contain?
Breathalyzers determine the alcohol content in a person's breath by the following (unbalanced) redox reaction: C2H5OH...
Breathalyzers determine the alcohol content in a person's breath by the following (unbalanced) redox reaction: C2H5OH + Cr2O72− → CH3CO2H + Cr3+ (acidic solution) If analysis of a breath sample generates 7.60 x 10-4 M Cr3+ ions in 35.0 mL, how many mg of alcohol did it contain?
6. The legal definition of intoxication in some states is a blood alcohol (C2H5OH) level of 0.1% (by mass) or higher. A...
6. The legal definition of intoxication in some states is a blood alcohol (C2H5OH) level of 0.1% (by mass) or higher. A given analysis requires 48.02 ml of 0.05182 M K2C1207 to titrate a 48.91 g sample of blood Assume only C2H50H reacts with K2Cr207 to produce Cr' (aq), CO2 (g), and H20 (1). Was the person this blood was taken from legally intoxicated?
6. The legal definition of intoxication in some states is a blood alcohol (C2H5OH) level of...
Part A. Which of the following is not a redox reaction? H2O(l) + NH3(g) NH4+(aq)...
Part A. Which of the following is not a redox reaction?
H2O(l) + NH3(g) NH4+(aq) + OH–(aq)
2H2(g) + O2(g) 2H2O(l)
Zn(s) + H2SO4(aq) ZnSO4(aq) + H2(g)
FeSO4(aq) + K2Cr2O7(aq) + 7H2SO4(aq) Cr2(SO4)3(aq) + 3Fe2(SO4)3(aq) + K2SO4(aq)
+ 7H2O(l)
Cl2(g) + 2KBr(aq) Br2(l) + 2KCl(aq)
Part B. A 43.46 mL sample of Na2SO3 was titrated with 68.99 mL
of 0.128 M K2Cr2O7 solution in the presence of H2SO4. Calculate the
molarity of the Na2SO3 solution. Enter to 3 decimal...
The quantity of antimony in a sample can be determined by an oxidation–reduction titration with an...
The quantity of antimony in a sample can be determined by an oxidation–reduction titration with an oxidizing agent. A 9.73 sample of stibnite, an ore of antimony, is dissolved in hot, concentrated HCl(aq) and passed over a reducing agent so that all the antimony is in the form Sb3+(aq). The Sb3+(aq) is completely oxidized by 50.2 mL of a 0.110 M aqueous solution of KBrO3(aq). The unbalanced equation for the reaction is BrO−3(aq)+Sb3+(aq)⟶Br−(aq)+Sb5+(aq)(unbalanced) Calculate the amount of antimony in the...
1 Review | Constants | Periodic Table Alcohol levels in blood can be determined by a redox titration with potassium dichromate according to the balanced equation C2H5OH (aq) + 2Cr2O2 (aq) +16H+ (aq) → 2CO2 (g) + 4Cr3+ (aq) +11H2O (1) Part A What is the blood alcohol level in mass percent if 8.05 mL of 0.04988 M K2Cr2O7 is required for titration of a 10.000 g sample of blood?
6. The legal definition of intoxication in some states is a blood alcohol (C2H5OH) level of 0.1% (by mass) or higher. A given analysis requires 48.02 ml of 0.05182 M K2C1207 to titrate a 48.91 g sample of blood Assume only C2H50H reacts with K2Cr207 to produce Cr' (aq), CO2 (g), and H20 (1). Was the person this blood was taken from legally intoxicated?
6. The legal definition of intoxication in some states is a blood alcohol (C2H5OH) level of...
Part A. Which of the following is not a redox reaction?
H2O(l) + NH3(g) NH4+(aq) + OH–(aq)
2H2(g) + O2(g) 2H2O(l)
Zn(s) + H2SO4(aq) ZnSO4(aq) + H2(g)
FeSO4(aq) + K2Cr2O7(aq) + 7H2SO4(aq) Cr2(SO4)3(aq) + 3Fe2(SO4)3(aq) + K2SO4(aq)
+ 7H2O(l)
Cl2(g) + 2KBr(aq) Br2(l) + 2KCl(aq)
Part B. A 43.46 mL sample of Na2SO3 was titrated with 68.99 mL
of 0.128 M K2Cr2O7 solution in the presence of H2SO4. Calculate the
molarity of the Na2SO3 solution. Enter to 3 decimal...
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