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Given a distortionless cable for 250 MHz. The outer radius is 20 mm. Assume copper conductors...

Given a distortionless cable for 250 MHz. The outer radius is 20 mm. Assume copper conductors are thick (σc = 5.7×107 S/m). The medium has σ = 10-5 S/m, μ = μ0, ε = ε0. (a) Please design the radius of the inner conductor, so this transmission the line can be distortionless; (b) Calculate the characteristic impedance of this line and its attenuation constant; (c) Calculate the distance of at most 10 dB attenuation.

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Answer #1

using the formulas I had written in my image, we can easily calculate the inner radius,

for distortionless cable: RC=LG

(a)inner radius=14.02mm

(b)characteristic impedence=approx 21.3 ohms and then attenuation constant=as calculated above have no units

(c)Here I need some more data to find the distance

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