Suppose Pep/9 contains four hexadecimal values: A: 19AC X: FE20 Mem[0A3F]: FF00 Mem[0A41]: 103D What are...
Suppose Pep/9 contains four hexadecimal values:
A: 19AC
X: FE20
Mem[0A3F]: FF00
Mem[0A41]: 103D
What are the those values after executing F10A41?
A. A= 096C X=FEFF Mem[0A3F]=FE20 Mem[0A41]=103D
B. A= 19AC X=FEFF Mem[0A3F]=FF00 Mem[0A41]=19AC
C. A= E653 X=FEFF Mem[0A3F]=FF20 Mem[0A41]=AC3D
D. A= 19AC X=FE20 Mem[0A3F]=FF00 Mem[0A41]=AC3D
Homework Answers
Ans:
After exexuting F10A41, the answer would be the option 'D'.
Which means after execution the F10A41,,, As F1 is equal to store byte accumulator.
A = 19AC,
X = FE20,
MeM[0A3F] = FF00,
MeM[0A41] = AC3D
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