Helium-filled balloons are used to carry scientific instruments high into the atmosphere. Suppose a balloon is launched when the temperature is 22.5 °C, and the barometric pressure is 751 mm Hg. If the balloon’s volume is 4.34×104 L (and no helium escapes from the balloon), what will the volume be at a height of 20 miles, where the pressure is 76.0 mm Hg, and the temperature is -33.0 °C
Solution:
According to ideal gas equation,
P1V1/T1 = P2V2/T2
Where,
P1 = 751 mm Hg
V1 = 4.34 x 10^4 L
T1 = 22.5 + 273 = 295.5
P2 = 76 mm Hg
T2 = 273 -33 = 240 K
V2 = ?
Therefore,
V2 = P1V1T2 / P2T1
= 751 x 4.34 x 10^4 x 295.5 / 76 x 240
= 5.28 x 10^5 L
Thus, volume will be 5.28 x 10^5 L
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