A cube made of platinum (Pt) has an edge length of 1.50 cm. The density of...
A cube made of platinum (Pt) has an edge length of 1.50 cm. The density of Pt is 21.45 g/cm3.
(a) Calculate the number of Pt atoms in the cube.
(b)Atoms are spherical in shape. Therefore, the Pt atoms in the cube cannot fill all the available space. If only 74.0 percent of the space inside the cube is taken up by Pt atoms, calculate the radius in picometers of a Pt atom. The mass of a single Pt atom is 3.240 × 10−22 g. [The volume of a sphere of radius r is (4/3) πr3. The volume of a cube is l3, where l is the length of a side. Avogadro's number is 6.022 × 1023.]
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A cube made of platinum (Pt) has an edge length of 1.50 cm. The
density of...
Atoms are spherical in shape. Therefore, the Pt atoms in the cube cannot fill all the...
Atoms are spherical in shape. Therefore, the Pt atoms in the cube cannot fill all the available space. If only 74.0 percent of the space inside the cube is taken up by Pt atoms, calculate the radius in picometers of a Pt atom. The mass of a single Pt atom is 3.240 times 10^-22 g. [The volume of a sphere of radius r is (4/3) pi r^3. The volume of a cube is l^3, where l is the length of...
A pure copper cube has an edge length of 1.30 cm . Part A How many...
A pure copper cube has an edge length of 1.30 cm . Part A How many copper atoms does it contain? (volume of a cube = (edge length)3; density of copper = 8.96 g/cm3) N= Cu atoms
What is the edge length of a 307-g iron cube? (The density of iron is 7.86...
What is the edge length of a 307-g iron cube? (The density of iron is 7.86 g/cm3, and the volume of a cube is equal to the edge length cubed.)
Calculate the mass a cube of platinum of edge length 0.040mm the density 21.4g/cm^3. V=4/3 (pie)(r).
Calculate the mass a cube of platinum of edge length 0.040mm the density 21.4g/cm^3. V=4/3 (pie)(r).
Please answer 2,3,4 2. How many platinum (Pt) atoms are in a cube that is I...
Please answer 2,3,4
2. How many platinum (Pt) atoms are in a cube that is I mm on each side? What is the average volume occupied by each atom? (Divide the total volume by the number of atoms in the volume.) 3. What is the side of a cube holding exactly 1 mol of gold (Au) atoms? Assume that the equilibrium separation distance of the ions in sodium fluoride (NaF) is the sum of the Na and F ionic radii....
The crystal structure of copper is face-centered cubic (fcc), in which atoms touch along the face...
The crystal structure of copper is face-centered cubic (fcc), in which atoms touch along the face diagonal. Copper has a density of 8.92 g/cm3 . Taking Avogadro's number to be 6.022 x 1023 atoms per mole and the molar mass of copper to be 63.55 g/mol, calculate the atomic radius of a copper atom.
a) a sphere of gold with a radius of 12.1 cm. (The volume of a sphere...
a) a sphere of gold with a radius of 12.1 cm. (The volume of a sphere with a radius r is V = (4/3) π r3; the density of gold is 19.3 g/cm3.) -answer in scientific notation (b) a cube of platinum of edge length 0.024 mm (density = 21.4 g/cm3).- answer in scientific notation (c) 66.9 mL of ethanol (density = 0.798 g/mL).- answer in scientific notation
Unit Cell Calculations Name _____________________________ Unit Cells: The Simplest Repeating Unit in a Crystal The structure...
![](https://lh4.googleusercontent.com/K_IdXKabFLhtXXOIgQQGWz-LYlYNPa5z9cPt6FQy3eCY_hrY26qZS8XFBDdXJxqT5rgw1lAAnw6EBuTmrr7-OGOL5RkSwGNWJ97ys65Nc5ZjNeeCGSQ-UGT6SRqFEqehUHwDJLPp" aria-describedby="jt3"><img alt="unitcell1.png)
Unit Cell Calculations Name
_____________________________
Unit Cells: The Simplest Repeating Unit in a Crystal
The structure of solids can be described as if they were
three-dimensional analogs of a piece of wallpaper. Wallpaper has a
regular repeating design that extends from one edge to the other.
Crystals have a similar repeating design, but in this case the
design extends in three dimensions from one edge of the solid to
the other. We can unambiguously describe a piece of wallpaper by...
NaCl has a rock salt crystal structure with a unit cell edge length of 0.56 nm....
NaCl has a rock salt crystal structure with a unit cell edge length of 0.56 nm. The atomic weights of the Na and Cl are 23 and 35.5 g/mol, respectively, and the Avogadro's number is 6.022 x 10“ formula units/mol. (a) Draw a unit cell to show the crystal structure of the NaCl. (b) What is the coordination number of the atoms in this structure? (c) How many Na atoms and Cl atoms in one unit-cell of such a structure?...
A cube of iron, which has a density of 7.87 g/cm3, has an edge length of...
A cube of iron, which has a density of 7.87 g/cm3, has an edge length of 3.75 cm. What is the mass of the sample?
Atoms are spherical in shape. Therefore, the Pt atoms in the cube cannot fill all the available space. If only 74.0 percent of the space inside the cube is taken up by Pt atoms, calculate the radius in picometers of a Pt atom. The mass of a single Pt atom is 3.240 times 10^-22 g. [The volume of a sphere of radius r is (4/3) pi r^3. The volume of a cube is l^3, where l is the length of...
Please answer 2,3,4
2. How many platinum (Pt) atoms are in a cube that is I mm on each side? What is the average volume occupied by each atom? (Divide the total volume by the number of atoms in the volume.) 3. What is the side of a cube holding exactly 1 mol of gold (Au) atoms? Assume that the equilibrium separation distance of the ions in sodium fluoride (NaF) is the sum of the Na and F ionic radii....
NaCl has a rock salt crystal structure with a unit cell edge length of 0.56 nm. The atomic weights of the Na and Cl are 23 and 35.5 g/mol, respectively, and the Avogadro's number is 6.022 x 10“ formula units/mol. (a) Draw a unit cell to show the crystal structure of the NaCl. (b) What is the coordination number of the atoms in this structure? (c) How many Na atoms and Cl atoms in one unit-cell of such a structure?...
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