Find the values of t that bound the middle 0.8 of the
distribution for df = 30. (Give your answers correct to two decimal
places.)
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solution :
Given that,
Degrees of freedom = 30
Using standard normal table,
P( -t < t < t) = 0.8
= P(t < t) - P(t <-t ) = 0.8
= 2P(t < t) - 1 = 0.8
= 2P(t < t) = 1 + 0.8
= P(t < t) = 1.8 / 2
= P(t < t) = 0.9
= P(t < 1.310) = 0.9
= t ± 1.31
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