Calculate the bond order for an ion with this configuration. (σ2s)2(σ2s)2(σ2px)2(π2py, π2pz)4(π2py, π2pz*)1

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Question

Calculate the bond order for an ion with this configuration. (σ2s)2(σ2s*)2(σ2px)2(π2py, π2pz)4(π2py*, π2pz*)1

Answer 1

Answer #1

Answer :- 2.5

the bond order for an ion with this configuration. (σ2s)²(σ2s*)²(σ2px)²(π2py, π2pz)⁴(π2py*, π2pz*)¹

since we know that,

bond order = ( electrons in bonding - electrons in antibonding) / 2

electrons in bonding = 8

electrons in antibonding = 3

bond order = (8 - 3 ) / 2

bond order = 5/2

bond order = 2.5

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Answer 2

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Calculate the bond order for an ion with this configuration. (σ2s)2(σ2s*)2(σ2px)2(π2py, π2pz)4(π2py*, π2pz*)1