Question

for the reaction 2CO + O2 = 2CO2 it is found that at a certain temperature...

for the reaction 2CO + O2 = 2CO2 it is found that at a certain temperature the concentration are [CO] = 7.2 x 10^-4 M, [O2] = 8.1 x 10^-3 M, and [CO2] = 2.3 x 10-2 M. write out the equilibrium expression and calculate K for the reaction at this temperature?

How would the equilibrium position change if CO2 was added?

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Answer #1

2 CO (g) + O2 (g) 2 CO2 (g)

equilibrium constant, K = [CO2]2 / ([CO]2[O2])

K = (2.3 x 10-2 M)2 / [(7.2 x 10-4 M)2 * (8.1 x 10-3 M)]

K = 1.26 x 105

If CO2 is added then the reaction would shift backwards so that the added CO2 is consumed and equilibrium can be achieved again

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