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How do you calculate potential V given Zn + Br2 (sat'd) -> Zn^2+ (0.10M) + 2Br-(0.5M)...

How do you calculate potential V given

Zn + Br2 (sat'd) -> Zn^2+ (0.10M) + 2Br-(0.5M)

Our measured potential (V) was 1.81. and the formula we used was Ecell= E^0cell - (0.0592)/n * log Q

also, which substance is oxidized? which substance acts as the cathode, the e- flow FROM which electrode, and the e- flow TO which electrode?
Thanks.

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