Question

How much heat (in joules) is required to raise the temperature of 34.0 kg of water from 24 ∘C to 89 ∘C? The specific heat of water is 4186 J/kg⋅C∘. Express your answer using two significant figures.

Answer 1

Mass of water, m = 34.0 kg

Initial temperature of water, T1 = 24 deg C

Final temperature of water, T2 = 89 deg C

Specific heat of water, s = 4186 J/kg*C

Quantity of heat required to raise the temperature of water from temperature T1 to T2 is given as -

Q = m*s*(T2 - T1)

= 34.0*4186*(89 - 24)

= 9251060 J = 9.20 x 10^6 J (in two significant digits) (Answer)