17.3 #2 For ethanol, C2H5OH, the heat of fusion at its normal melting point of -115...
17.3 #2
For ethanol,
C2H5OH, the heat of fusion
at its normal melting point of -115 °C is
5.0 kJ/mol.
The entropy change when 1.51 moles of liquid
C2H5OH freezes at
-115 °C, 1 atm is ______ J/K.
Homework Answers
entropy change at melting point = dHfusion/Tm
given ,Tm = -115 C= 273 K -115 = 158 K
dHfusion = 5 KJ/mol = 5000 J/mol , tho=is is for 1 mole ethanol
entropy change for 1.51 mol ethanol , dS= 1.51* 5000 j/mol/158 K = 47.7848 j/K
since liquid changes to solid , entropy reduced. Hence sign entropy will be negative
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17.3 #2
For ethanol,
C2H5OH, the heat of fusion
at its normal melting point of -115...
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