ZuoTi.Pro
Question

A sample survey interviews an SRS of 207 college women. Suppose that 68% of all college...

A sample survey interviews an SRS of 207 college women. Suppose that 68% of all college women have been on a diet within the last 12 months. What is the probability that 73% or more of the women in the sample have been on a diet?

Use 4 decimal places.

math   Statistics-And-Probability   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

Number of women on diet

Mean = n*p = 207*0.68 = 140.76

Standard dev = (n*p*q)^0.5 = (207*0.68*0.32)^0.5 = 6.711

Now 73% = 207*0.73 = 151.11

P(x>151.11) = 0.0618

0 0
Add a comment
Know the answer?
Add Answer to:
A sample survey interviews an SRS of 207 college women. Suppose that 68% of all college...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • 3. A sample survey interviews an SRS of 267 college women. Suppose (as is roughly true)...

    3. A sample survey interviews an SRS of 267 college women. Suppose (as is roughly true) that 64 % of all college women have been on a diet within the past 12 months. What are the mean and standard deviation of the sampling distribution for samples of 267 women? The mean of the sampling distribution, p = (+ 0.01) The standard deviation of the sampling distribution of p-hat = (+ 0.01) Use a Normal approximation to find the probability that...

  • 6. A sample survey interviews an SRS of 265 college wo men. Suppose as is roughly...

    6. A sample survey interviews an SRS of 265 college wo men. Suppose as is roughly true that 68 % of all college women have been on a diet within the past 2 months. What are the mean and standard deviation of the sampling distribution for samples of 265 women? The mean of the sampling distribution, p-+0.01) The standard deviation of the sampling distribution of p-hat- 0.01) Use a Normal approximation to find the probability that 81 % or more...

  • )A sample survey interviews an SRS of 267 college women. Suppose(as is roughly true) that 70%...

    )A sample survey interviews an SRS of 267 college women. Suppose(as is roughly true) that 70% of all college women have been on a diet within the past 12months. (a) What are the mean and standard deviation of the sampling distribution of the sample proportion ˆpin random samples of size 267? (b) Explain why, under these conditions, the sampling distribution of ˆpis approximately normal. (c) Using the normal approximation, find the probability that 76% or more of the women in...

  • Suppose that 88% of college men and 84% of college women were employed last summer, based on a sample survey that interv...

    Suppose that 88% of college men and 84% of college women were employed last summer, based on a sample survey that interviewed SRSs of 400 college men and 400 college women. The two samples were independent. a) What is the approximate distribution of the proportion p̂F of women who worked last summer? What is the approximate distribution of the proportion p̂M of men who worked? b) The survey wants to compare men and women. What is the approximate distribution of...

  • A government sample survey plans to measure the LDL (bad) cholesterol level of an SRS of...

    A government sample survey plans to measure the LDL (bad) cholesterol level of an SRS of men aged 20 to 34. Suppose that in fact the LDL cholesterol level of all men aged 20 to 34 follows the Normal distribution with mean μ = 119 milligrams per deciliter (mg/dL) and standard deviation   σ = 25 mg/dL. Use Table A for the following questions, where necessary. (a) What is the probability that x takes a value between 116 and 122 mg/dL?...

  • Suppose that 88% of college men and 84% of college women were employed last summer. A...

    Suppose that 88% of college men and 84% of college women were employed last summer. A sample survey interviewed SRSs of 400 college men and 400 college women. The two samples were independent. a) What is the approximate distribution of the proportion pF of women who worked last summer? What is the approximate distribution of the proportion pM of men who worked? b) The survey wants to compare men and women. What is the approximate distribution of the difference in...

  • 3. Suppose that 88% of college men and 84% of college women were employed last summer,...

    3. Suppose that 88% of college men and 84% of college women were employed last summer, based on a sample survey that interviewed SRSs of 400 college men and 400 college women. The two samples were independent. a) What is the approximate distribution of the proportion pF of women who worked last summer? What is the approximate distribution of the proportion pM of men who worked? Write your answer in a Text Box. b) The survey wants to compare men...

  • A random sample of adult drivers was obtained, 53% men and 46% women. A survey showed...

    A random sample of adult drivers was obtained, 53% men and 46% women. A survey showed that 57% of the drivers rely on GPS systems. 32% of the drivers are men and use GPS while 24% of the drivers are women and use GPS. Suppose a person included in this survey is randomly selected. a.) Suppose the person selected is a man. What is the probability that he relies on a GPS system? Your answer should have at least 3...

  • A random sample of adult drivers was obtained, 55% men and 43% women. A survey showed...

    A random sample of adult drivers was obtained, 55% men and 43% women. A survey showed that 57% of the drivers rely on GPS systems. 32% of the drivers are men and use GPS while 21% of the drivers are women and use GPS. Suppose a person included in this survey is randomly selected. a) Suppose the person selected is a man. What is the probability that he relies on a GPS system? Your answer should have at least 3...

  • We have survey data on the body mass index (BMI) of 668 young women. The mean...

    We have survey data on the body mass index (BMI) of 668 young women. The mean BMI in the sample was x = 25. We treated these data as an SRS from a Normally distributed population with standard deviation σ = 8. (a) Suppose that we had an SRS of just 112 young women. What would be the margin of error for 95% confidence? (Round your answer to four decimal places.) (b) Find the margins of error for 95% confidence...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT