Question

C#

Use a one-dimensional array to solve the following problem: A company pays its salespeople on a commission basis. The salespeople receive $200 per week plus 9% of their gross sales for that week. For example, a salesperson who grosses $5000 in sales in a week receives $200 plus 9% of $5000, or a total of $650. Write an application (using an array of counters) that determines how many of the salespeople earned salaries in each of the following ranges (assume that each salesperson’s salary is truncated to an integer amount): The application will accept sales amount until the user enters -1 a) $200–299 b) $300–399 c) $400–499 d) $500–599 e) $600–699 f) $700–799 g) $800–899 h) $900–999 i) $1000 and over

Answer 1

C SHARP CODE:

using System;

class MainClass {

    public static void Main (string[] args) {

        // Assuming there are max 100 sales persons

        int[] salary = new int[100];

        int size = 0, sales;

        Console.Write("Enter sales amount: ");

        // userInput = Console.Read();

        sales = Int32.Parse(Console.ReadLine());

        while(sales != -1){

            salary[size] = 200 + sales*9/100;

            size++;

            Console.Write("Enter sales amount: ");

            sales = Int32.Parse(Console.ReadLine());

        }

        Console.WriteLine("a) $200-299: " + getCount(salary, size, 200, 299).ToString());

        Console.WriteLine("b) $300-399: " + getCount(salary, size, 300, 399).ToString());

        Console.WriteLine("c) $400-499: " + getCount(salary, size, 400, 499).ToString());

        Console.WriteLine("d) $500-599: " + getCount(salary, size, 500, 599).ToString());

        Console.WriteLine("e) $600-699: " + getCount(salary, size, 600, 699).ToString());

        Console.WriteLine("f) $700-799: " + getCount(salary, size, 700, 799).ToString());

        Console.WriteLine("g) $800-899: " + getCount(salary, size, 800, 899).ToString());

        Console.WriteLine("h) $900-999: " + getCount(salary, size, 900, 999).ToString());

        Console.WriteLine("i) $1000 and over: " + getCount(salary, size, 1000, -1).ToString());

        

    }

    // Function to get number of salesperson between given salary range

    // both start and end inclusive

    public static int getCount(int[] salary, int size, int start, int end){

        int count = 0;

        for(int i = 0; i < size; i++){

            // Special case for 1000 and above

            if(start == 1000 && end == -1 && salary[i] >= start)

                count++;

            if(start <= salary[i] && salary[i] <= end)

                count++;

        }

        return count;

    }

}

SAMPLE OUTPUT:

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